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2 years ago

Help me! I'm having trouble with this

Mathematics

1 answer:

harkovskaia [24]2 years ago

6 0

Answer:

Its C. I can't answer the answer in the brainly answers. sorry. But check on Math Papa and put the first equation, the second equation and you will have the graph below. But in conclusion its C.

Step-by-step explanation:

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A shop is having a sale all items are reduced work out the sale price of an item normally priced at £60

Naddik [55]

Question:

A shop is having a sales all items are reduced by 25%. Work out the sale price of an item normally priced at £60?

Answer:

The new price is £45

Step-by-step explanation:

Given

$Sales\ price = \pounds 60$

$Rate = 25\%$

First, calculate the reduction

$Reduction = Rate * Sales\ price$

$Reduction = 25\% * \pounds 60$

$Reduction = \pounds 15$

The new price is:

$New = Sales\ price - Reduction$

$New = \pounds 60 - \pounds 15$

$New = \pounds 45$

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2 years ago

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ddd [48]

Answer: eh

Step-by-step explanation:

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2 years ago

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Help!! <br><br><br><br> These graph questions will drive me crazy

koban [17]

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3 years ago

The dimensions of a rectangular field are 16x - 6 and 10x + 12 units. The value of x for which it would be square is______.

Simora [160]

I honestly dont know lol

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2 years ago

Estimate the minimum number of subintervals to approximate the value of Integral from negative 3 to 3 (2 x squared plus 9 )dx wi

vichka [17]

Answer:

The value of n for (a) n=425. (b) n=0.

Step-by-step explanation:

Given integration is,

$\int_{-3}^{3}f(x)=\int_{-3}^{3}(2x^2+9)dx$

(a) For Trapezoidal Rule : Composite error is,

$E_T=-\frac{(b-a)^3}{12n^2}f''(x_m)$

Where, f''(x_m)=greatest value of |f''(x)|= |4|=4, a=-3, b=3. Therefore to find the minimum number of subinterval,

$|E_T|\leq | \frac{(b-a)^3}{12n^2}f''(x)|$ |

$\leq \frac{4(-3-3)^3}{12n^2}$

$=\frac{72}{n^2}$

According to the question, we must choose n such that,

$\frac{72}{n^2}$

$\implies n>424.2640686$

So we can take n=425.

(b) For Simpson 1/3 rule : Composite error is,

$E_S=-\frac{(b-a)^5}{180n^4}f^{(iv)}(x_m)$

where, $f^{(x_m)}=\textit{greatest value of} |f^{(iv)}(x)|$

In this problem $f^{(iv)}(x)=0$ , so that,

$|E_S|\leq 0$

that is there exist no error. So n=0.

6 0

2 years ago

Help me! I'm having trouble with this​

Help me! I'm having trouble with this