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strojnjashka [21]

3 years ago

5

A bank's monthly charge for maintaining an account is $.45 for each check written plus a service charge of $12.50. If x represen

ts the number of checks written during the month, which function models this situation?

2 answers:

ExtremeBDS [4]3 years ago

6 0

Answer:

0.45x + 12.50

Step-by-step explanation:

Maksim231197 [3]3 years ago

5 0

The function would be 12.50+.45x

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Which students, if any, have correctly identified a base and its corresponding height? Which ones have not? Explain what is inco

muminat

Answer:

The Explanation is below .

Step-by-step explanation:

a. )

Raul is correct because Height should always be Perpendicular

and Raul has drawn Height 'h' Perpendicular to the corresponding Base 'b'.

b. )

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c. )

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6 0

3 years ago

Original content Copyright © by Houghton Mifflin Harcourt. Additions and changes to the original content are the responsibility

pashok25 [27]

Answer: a) D = √148

m = (-5,4)

b) D = √241

m = (1, 7.5)

c) D = √20

m = (0,-4)

Step-by-step explanation:

Distance and Midpoint Formulas

distance = D = √[(x₂-x₁)² + (y₂-y₁)²]

Midpoint: m = ((x₂+x₁)/2 , (y₂+y₁)/2)

(−4, 10) and (−6, −2)

D = √[(-6-(-4))² + (-2-10)²] = √[(-6+4))² + (-2-10)²] = √[(-2))² + (-12)²] =

√[4 + 144] = √148

m = ((-6+(-4))/2 ; (-2+10)/2

m = (-10/2 ; 8/2)

m = (-5,4)

(−1, 15) and (3, 0)

D = √[(3-(-1))² + (0-15)²] = √[(3+1))² + (0-15)²] = √[(4)² + (-15)²] =

√[16 + 225] = √241

m = ((3+(-1))/2 ; (0+15)/2

m = (2/2 ; 15/2)

m = (1,7.5)

(2, −3) and (−2, −5)

D = √[(-2-2)² + ((-5)-(-3)²] = √[(-4))² + (-5+3)²] = √[(-4)² + (-2)²] =

√[16 + 4] = √20

m = (-2+2))/2 ; (-5+(-3))/2

m = (0/2 ; -8/2)

m = (0,-4)

3 0

3 years ago

Students at an elementary school are given a questionnaire that they are required to return after their parents have completed i

Nostrana [21]

Yes. The 100 - 85 = 15, meaning 15% of parents said yes. 85 > 15

6 0

3 years ago

Area of the bounded curves y=x^2, y=√(7+x)

N76 [4]

Answer:

$\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 5.74773$

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

U-Substitution

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

<u>Step 1: Define</u>

$\displaystyle \left \{ {{y = x^2} \atop {y = \sqrt{7 + x}}} \right.$

<u>Step 2: Identify</u>

<em>Graph the systems of equations - see attachment.</em>

Top Function: $\displaystyle y = \sqrt{7 + x}$

Bottom Function: $\displaystyle y = x^2$

Bounds of Integration: [-1.529, 1.718]

<u>Step 3: Integrate Pt. 1</u>

Substitute in variables [Area of a Region Formula]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - \int\limits^{1.718}_{-1.529} {x^2} \, dx$
[Right Integral] Integration Rule [Reverse Power Rule]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - \frac{x^3}{3} \bigg| \limits^{1.718}_{-1.529}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - 2.88176$

<u>Step 4: Integrate Pt. 2</u>

<em>Identify variables for u-substitution.</em>

Set <em>u</em>: $\displaystyle u = 7 + x$
[<em>u</em>] Basic Power Rule [Derivative Rule - Addition/Subtraction]: $\displaystyle du = dx$
[Limits] Switch: $\displaystyle \left \{ {{x = 1.718 ,\ u = 7 + 1.718 = 8.718} \atop {x = -1.529 ,\ u = 7 - 1.529 = 5.471}} \right.$

<u>Step 5: Integrate Pt. 3</u>

[Integral] U-Substitution: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{8.718}_{5.471} {\sqrt{u}} \, du - 2.88176$
[Integral] Integration Rule [Reverse Power Rule]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = \frac{2x^\Big{\frac{3}{2}}}{3} \bigg| \limits^{8.718}_{5.471} - 2.88176$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 8.62949 - 2.88176$
Simplify: $\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 5.74773$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0

3 years ago

How does sunlight cause cracks in the street

Zanzabum

Answer:

heat causes the concrete to crack and dissemble

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers