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3 years ago

Solve for b. 3-2(b-2)=2-7b3−2(b−2)=2−7b

Mathematics

1 answer:

lyudmila [28]3 years ago

3 0

Step-by-step explanation:

3 - 2(b - 2) = 2 - 7b

To solve this first distribute -2 to (b - 2)

3 + (-2b + (-2) x -2) = 2 - 7b

when we simplify this it becomes:

3 + (-2b + 4) = 2 - 7b

We take (-2b + 4) out of the parenthesis:

3 - 2b + 4 = 2 - 7b

Now simplify again.

7 - 2b = 2 - 7b

Now send all the b's to one side and constants on the other.

7 - 2 = -7b +2b

5 = 5b

b = 1

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Determine the value of y. (-7,y) (14,-5) A. 1.25 B. 2.5 C. 5 D. 10

Gnesinka [82]

It should be D, if -7x-2 is 14, then -5x-2 will be 10.

7 0

4 years ago

1 + tanx / 1 + cotx =2

Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer: x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0

3 years ago

The number 5/7 can be best described as a(n)

kirill [66]

Fraction. I think? I don't know exactly what your learning at the moment. I hope this helps

7 0

3 years ago

Read 2 more answers

Write an equation of the line passing through the points (4.15) and (-1. - 15).

jolli1 [7]

Answer:

y = 6x - 9

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step-by-step explanation:

Step 1: Define

Point (4, 15)

Point (-1, -15)

Step 2: Find slope m

Substitute: $m=\frac{-15-15}{-1-4}$
Subtract: $m=\frac{-30}{-5}$
Divide: $m=6$

Step 3: Find y-intercept b

Define: y = 6x + b
Substitute: -15 = 6(-1) + b
Multiply: -15 = -6 + b
Isolate b: -9 = b
Rewrite: b = -9

Step 4: Write linear equation

Substitute in all variables.

y = 6x - 9

And we have our answer!

4 0

3 years ago

4÷5/9 will give brainliest to right answer

klasskru [66]

Answer:

.0888 repeating

Step-by-step explanation:

4 ÷ 5 ÷ 9 work left to right

3 0

3 years ago

Read 2 more answers