8=2*2*2
27=3*3*3
16=2*2*2*2
81=3*3*3*3
Restul nu se intelege
Answer:
b
Step-by-step explanation:
Remember that the vertex form of a parabola or quadratic equation is:
y=a(x-h)^2+k, where (h,k) is the "vertex" which is the maximum or minimum point of the parabola (and a is half the acceleration of the of the function, but that is maybe too much :P)
In this case we are given that the vertex is (1,1) so we have:
y=a(x-1)^2+1, and then we are told that there is a point (0,-3) so we can say:
-3=a(0-1)^2+1
-3=a+1
-4=a so our complete equation in vertex form is:
y=-4(x-1)^2+1
Now you wish to know where the x-intercepts are. x-intercepts are when the graph touches the x-axis, ie, when y=0 so
0=-4(x-1)^2+1 add 4(x-1)^2 to both sides
4(x-1)^2=1 divide both sides by 4
(x-1)^2=1/4 take the square root of both sides
x-1=±√(1/4) which is equal to
x-1=±1/2 add 1 to both sides
x=1±1/2
So x=0.5 and 1.5, thus the x-intercept points are:
(0.5, 0) and (1.5, 0) or if you like fractions:
(1/2, 0) and (3/2, 0) :P
I don't get you but if you transform the equation to it's standard form, it will be
3x+4y=4
First, Multiply each term by 4:
y(4)=-3x/4(4)+1(4)
4y=-12x/4+4
4y=-3x+4
Now add 3x to both sides of the equation:
4y+3x=-3x+3x+4
3x+4y=0+4
3x+4y=4
So the diagonal of cube
this was a practice act question so her's the answer
look at the cube through one of the faces
you will see the diagonal as the hypotonuse of a triangle
and also a triangle on the floor (look at attachment)
the ,diagonal is 28
a^2+b^2=28^2
a=b since it is a cube
remember that this is a 45,45 triangle so therefor
a=b=x
c=x√2 so
28=x√2
divide both sides by √2
28/(√2)=x
the diagonal on the floor is 28/(√2)
the sides of the triangle form another 45 45 90 triangle with 28/(√2) as hyponuse so
a=b=x
c=x√2=28/(√2)
solve for x
x√2=28/(√2)
divide both sides by √2
same as mujlitply both sides by 1/(√2) so
28/(√2) times 1/(√2)=28/(2)=14
the answer of 1 diagonal is 14 cm
the answer is 14cm