All categories

3 years ago

F(x) = 4x + 3. f(5) = 23. Which number is the input?

Mathematics

2 answers:

melamori03 [73]3 years ago

4 0

Answer:

Step-by-step explanation:

Oksanka [162]3 years ago

3 0

B. 5 is the input

Step-by-step explanation:

f(x) = 4x + 3 f(5) = 23 Plug in 5 for x.

f(x) = 4(5) + 3

f(x) = 20 + 3

f(x) = 23

B. 5 is the input

You might be interested in

The path of a soccer ball is modeled by the function h(x) = -0.005x2 + 0.25x, where h is the height in meters and x is the horiz

NemiM [27]

The maximum height that the ball reaches is 3.125m. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

6 0

3 years ago

Evaluate b-(-1/8)+c where b=2 and c=-7/4

tatiyna

Answer:

3/8

Step-by-step explanation:

Evaluate b - -1/8 + c where b = 2 and c = -7/4:

b - (-1)/8 + c = 2 - (-1)/8 - 7/4

Put 2 + 1/8 - 7/4 over the common denominator 8. 2 + 1/8 - 7/4 = (8×2)/8 + 1/8 + (2 (-7))/8:

(8×2)/8 + 1/8 - (7×2)/8

8×2 = 16:

16/8 + 1/8 - (7×2)/8

2 (-7) = -14:

16/8 + 1/8 + (-14)/8

16/8 + 1/8 - 14/8 = (16 + 1 - 14)/8:

(16 + 1 - 14)/8

16 + 1 = 17:

(17 - 14)/8

| 1 | 7

- | 1 | 4

| 0 | 3:

Answer: 3/8

8 0

3 years ago

"A new bakery offers decorated sheet cakes for children’s birthday parties and other special occasions. The bakery wants the vol

Darya [45]

Answer:

$w = 9 \text{ inches}\\l = 13\text{ inches}\\h = 3\text{ inches}$

Step-by-step explanation:

We are given the following in the question:

Volume of cake = 351 cubic inches

Let x inches be the width of cake.

Width of cake, w =

$x\text{ inches}$

Then, length of cake,l =

$(x + 4)\text{ inches}$

Height of cake,h =

$\dfrac{x}{3}\text{ inches}$

Volume of cake = Volume of cuboid

$V = lwh$

Putting values, we get:

$351 = x(x+4)(\dfrac{x}{3})\\\\1053 = x^3 + 4x\\x^3+4x^2-1053= 0\\\\\text{For x = 9}\\(9)^3+4(9)^2-1053= 0$

Thus, dimensions of cake are:

$w = 9 \text{ inches}\\l = 13\text{ inches}\\h = 3\text{ inches}$

3 0

3 years ago

What is the inverse of the function f (x) = 3(x + 5)2 – 4, such that x ≤ –5?

natali 33 [55]

The ball followed a path modelled by the equation h = −0.001! + 0.5 + 2.5 where h is the height of the ball in feet and is the

distance in feet.
The ball followed a path modelled by the equation h = −0.001! + 0.5 + 2.5 where h is the height of the ball in feet and is the

distance in feet.

3 0

2 years ago

Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)

Svet_ta [14]

<h2>Answer:</h2>

$\boxed{x=1, \y=-1, \ z=2}$

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}$

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}$

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}$

Step 4: solve for z, then for y, then for x:

$\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}$

$-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}$

By substituting $y=-1 \ and \ z=2$ into the first equation, we get the $x$ . So:

$x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}$

6 0

4 years ago

Read 2 more answers