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Zepler [3.9K]
3 years ago
12

I need the angle of elevation

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0

Answer:

multiply and see what you get

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Hhhehdhdhdd dbdhshshsnnsmemsiskzmdbbdhdhdhdbdb sbdb
Ne4ueva [31]

Answer:

Please what are you trying to say

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Jessica wrote 6 6 6 on the board. what is another way to show 6 6 6 6
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Umm she could put 6 times 4
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Read 2 more answers
Factorize 12ab + 15ab2
soldi70 [24.7K]

Answer:

12ab +15ab²

3ab(4 + 5b)

Step-by-step explanation:

7 0
3 years ago
Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 4; B: the numbers add to 5
expeople1 [14]

Answer:

A:\\R=4\hspace{8}G=\{y\hspace{3} ;\hspace{3}1\leq y\leq 6 \}\hspace{3}y\in Z

B:\\R+G=5\hspace{8}R=\{x\hspace{3} ;\hspace{3}1\leq x \leq 6 \}\hspace{3}x\in Z\hspace{5}G=\{y\hspace{3} ;\hspace{3}1\leq y\leq 6 \}\hspace{3}y\in Z\hspace{3}and\hspace{3}R\neq G

C:\\R=\{x\hspace{3} ;\hspace{3}1\leq x \leq 6 \}\hspace{3}x\in Z\hspace{3}G=\{y\hspace{3} ;\hspace{3}1\leq y\leq 6 \}\hspace{3}y\in Z\hspace{5}R =3 \hspace{3}or\hspace{3}G=3

D:

R=\{x\hspace{3} ;\hspace{3}1\leq x \leq 6 \}\hspace{3}x\in Z\hspace{3}G=\{y\hspace{3} ;\hspace{3}1\leq y\leq 6 \}\hspace{3}y\in Z\hspace{5};\hspace{3}R+G\neq8

Step-by-step explanation:

Let:

R=The\hspace{3}number\hspace{3}shows\hspace{3}by\hspace{3}the\hspace{3}red\hspace{3}dice\\G=The\hspace{3}number\hspace{3}shows\hspace{3}by\hspace{3}the\hspace{3}green\hspace{3}dice

A:

This is easy, simply R=4, and we don't know the value of G, so:

R=4\hspace{8}G=\{y\hspace{3} ;\hspace{3}1\leq y\leq 6 \}\hspace{3}y\in Z

B: Be careful here, we know the numbers add to 5, so we don't know the exact value of R or G, because R could be 4 and G could be 1 or R could be 2 and green could be 3. However we can be sure that they can´t have the same value, because 5 is an odd number, if we add the same number to a number the result is always even: n+n=2n. So:

R+G=5\hspace{8}R=\{x\hspace{3} ;\hspace{3}1\leq x \leq 6 \}\hspace{3}x\in Z\hspace{5}G=\{y\hspace{3} ;\hspace{3}1\leq y\leq 6 \}\hspace{3}y\in Z\hspace{3}and\hspace{3}R\neq G

C: R is 3 or G is 3, that's the only thing we know, hence:

R=\{x\hspace{3} ;\hspace{3}1\leq x \leq 6 \}\hspace{3}x\in Z\hspace{3}G=\{y\hspace{3} ;\hspace{3}1\leq y\leq 6 \}\hspace{3}y\in Z\hspace{5}R =3 \hspace{3}or\hspace{3}G=3

D: Similar to B, we only know that the sum of R and G isn't 8:

R=\{x\hspace{3} ;\hspace{3}1\leq x \leq 6 \}\hspace{3}x\in Z\hspace{3}G=\{y\hspace{3} ;\hspace{3}1\leq y\leq 6 \}\hspace{3}y\in Z\hspace{5};\hspace{3}R+G\neq8

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