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Zolol [24]
3 years ago
7

Sean determines that the triangle shown in the diagram has angle measures of 40°, 40°, and 100°. Is Sean correct?

Mathematics
2 answers:
Evgen [1.6K]3 years ago
7 0

Answer:

Step-by-step explanation:

The two angles add to 80 degrees. Two remote angles always equal the exterior angle not connected to them.

That means that

x + 5 + x - 5 = 80

2x = 80

x = 40

The base angle  is

40 + 40 + y = 180

80 + y = 180

y = 100

Note

You could do this much quicker by noticing that

80 + y = 189

y = 100

No he is not right

The given 2 angles are x + 5 which is 45 and x - 5 which is 35

All he got correct was the fact that the third angle is 100 degrees.

kotykmax [81]3 years ago
6 0
The bottom left angle is 180 -80=(100)

So the remaining 2 angles are equal 80
As all angles in a triangle are equal to 180

X+5 + x - 5 =80
Simplify
2x=80
X=40

Soo one of the angles are 40-5 which is (35)
And the other is 40+5 which is (45)
So sean is not correct
~sorry sean teehee
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Use the info given to find the new price: original price: $24 and discount rate: 11%. What is the new price????
ELEN [110]
So I think you have to find 11% of 24 and that is 11/100 x 24 = 2.64$. Then you reduce it to the real price 24-2.64= 21.36$ (the new prize). I might be completly wrong but I hope this helps
3 0
3 years ago
1.) Determine the type of solutions for the function (Picture 1)
NNADVOKAT [17]

Answer:

1) 2 nonreal complex roots

2) 1 Real Solution

3) 16

4) Reflected, narrower by a factor of 2/5, slides right 4 units and slides up 6 (units)

Step-by-step explanation:

1) The graph does not intercept the x-axis, therefore, there are no real solutions at the point y = 0

We get;

y = a·x² + b·x + c

At y = 6, x = -2

Therefore;

6 = a·(-2)² - 2·b + c = 4·a - 2·b + c

6 = 4·a - 2·b + c...(1)

At y = 8, x = 0

8 = a·(0)² + b·0 + c

∴ c = 8...(2)

Similarly, we have;

At y = 8, x = -4

8 = a·(-4)² - 4·b + c = 16·a - 4·b + 8

16·a - 4·b = 0

∴ b = 16·a/4 = 4·a

b = 4·a...(3)

From equation (1), (2) and (3), we have;

6 = 4·a - 2·b + c

∴ 6 = b - 2·b + 8 = -b + 8

6 - 8 = -b

∴ -b = -2

b = 2

b = 4·a

∴ a = b/4 = 2/4 = 1/2

The equation is therefor;

y = (1/2)·x² + 2·x + 8

Solving we get;

x = (-2 ± √(2² - 4 × (1/2) × 8))/(2 × (1/2))

x =( -2 ± √(-12))/1 = -2 ± √(-12)

Therefore, we have;

2 nonreal complex roots

2) Give that the graph of the function touches the x-axis once, we have;

1 Real Solution

3) The given function is f(x) = 2·x² + 8·x + 6

The general form of the quadratic function is f(x) = a·x² + b·x + c

Comparing, we have;

a = 2, b = 8, c = 6

The discriminant of the function, D = b² - 4·a·c, therefore, for the function, we have;

D = 8² - 4 × 2 × 6 = 16

The discriminant of the function, D = 16

4.) The given function is g(x) = (-2/5)·(x - 4)² + 6

The parent function of a quadratic equation is y = x²

A vertical translation is given by the following equation;

y = f(x) + b

A horizontal to the right by 'a' translation is given by an equation of the form; y = f(x - a)

A vertical reflection is given by an equation of the form; y = -f(x) = -x²

A narrowing is given by an equation of the form; y = b·f(x), where b < 1

Therefore, the transformations of g(x) from the parent function are;

g(x) is a reflection of the parent function, with the graph of g(x) being narrower by 2/5 than the graph of the parent function. The graph of g(x) is shifted right by 4 units and is then slides up by 6 units.

7 0
2 years ago
HELPPPPPPPPPPPPPPPPP!!
goldfiish [28.3K]

Answer:

option 3

Step-by-step explanation:

V= πr²h

to make h the subject

h= V÷πr²

just take πr² to the other side

as it in multiplication on the left hand side, it will in division in right hand side.

hope it helps!

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The domain of rational function gis the same as the domain of rational function f. Both f and g have a single x-intercept at x =
Irina-Kira [14]
The answer for this is D
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Answer:

Step-by-step explanation:3,360 is your answer

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