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bogdanovich [222]
3 years ago
14

Which shape has 3 sides and 3 corners?

Mathematics
2 answers:
IrinaK [193]3 years ago
7 0
The second one the one that is purple
lesya692 [45]3 years ago
3 0
Triangles have 3 sides and 3 corners so it’s the middle option, the purple triangle
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Noah is thinking of two fractions that have a sum of 35. Each fraction has a numerator of 1.
Zinaida [17]

The denominators of the fractions are 2 and 10.

<h3>The fractions with numerators of 1 that have sum of 3 / 5  is calculated below</h3>

The sum of the fractions are 3 / 5. Each of the fractions have a numerator of 1. Therefore, let the denominators be x and y

  • 1 / x + 1 / y = 3 / 5

Therefore,

1 / x  + 1 / y = 3 / 5

y + x / xy = 3 / 5

cross multiply

5y + 5x = 3xy

Using hit and trial method,

5(2) + 5(10) = 3(10)(2)

10 + 50 = 60

60 = 60

The values are same.

Therefore, the denominators are 2 and 10.

learn more on fraction here: brainly.com/question/11849602?referrer=searchResults

7 0
3 years ago
PLZ HELP I OVER SLEPT PLZ HELP ME ANSWER THIS QUESTION PLZ
Nikolay [14]

Answer:

Because without the time, there's no amount of water in the water tank.

Step-by-step explanation:

For every 10 minutes, the amount of water in the water tank is the time multiplied by 5.  Without the time for the water to rise, there's no water being added. So the water is dependent on the time to get it to a higher level. Sorry if this doesn't make much sense. Though I hope this helps!

4 0
3 years ago
Help I need help ON THISSSS
VikaD [51]

Answer:

ms girll i think you multiply

6 0
3 years ago
Read 2 more answers
What is the exact area and arc length of these sectors? Please helppp
Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = \frac{90}{360} \times \pi \times 12^2 = 36\pi

2. Area of sector 2 = \frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi

3. Area of sector 3 = \frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi

4. Area of sector 4 = \frac{270}{360} \times \pi \times 6^2 = 27 \pi

5. Arc length of sector 1 = \frac{90}{360} \times 2 \times \pi \times 12 = 6\pi

6. Arc length of sector 2 = \frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi

7. Arc length of sector 3 = \frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi

8. Arc length of sector 4 = \frac{270}{360} \times 2 \times \pi \times 6 = 9\pi

4 0
3 years ago
Sorry for the quality, if anyone could help. It’s geometry.
user100 [1]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
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