What is the value of 56.13?

Can you PLEASE HELP ME? I’ll give you brainliest if you answer PLEASE

egoroff_w [7]

It would be 9 inches squared, hope this helps!

8 0

3 years ago

How do you find the area of a composite figure?

Orlov [11]

Answer:

See below.

Step-by-step explanation:

Top prism:

To find the volume of the top prism, multiply the area of the base by the height. This is 1/2 times width times height times length.

V =1/2 l*w*h =1/2* 3*2.8*8 = 33.6

To find the surface area of a prism, find the area of the triangular base and the area of each rectangular side.

Area of the base is A = 1/2 * b*h = 1/2 * 3 * 8 = 12. Since there are 2 bases, the area is 24.

Area of the rectangular side is A = b*h = 2.8*5 = 14. Since there are two, the area is 2*14 = 42.

The surface area of the prism is 24 + 28 = 52.

Bottom prism:

To find the volume of the bottom prism, multiply the width times the height times the length.

V = l*w*h = 8*2.8*4.8 = 107.52

To find the surface area of the bottom prism, find the area of the base and each side of the house.

A = 8*2.8 = 22.4

A = 8*4.8 = 38.4 which occurs twice so it has a total area of 76.8

A = 2.8*4.8 = 13.44 which occurs twice so it has an area of 26.88.

The total volume is 33.6 + 107.52 = 141.12

The total surface area is 52 + 22.4 + 76.8 + 26.88 = 178.08

6 0

3 years ago

PLEASE HELP ASAP<br> A 18<br> B 13<br> C 11<br> D 14

AVprozaik [17]

ive done this the answer is B

7 0

3 years ago

I need help please, I am so confused.

vazorg [7]

Answer:

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

Therefore, to find the x-intercepts, substitute y = 0 and solve for x.

The vertex is the turning point: the minimum point of a parabola that opens upward, and the maximum point of the parabola that opens downward. As a parabola is symmetrical, the x-coordinate of the vertex is the midpoint of the x-intercepts.

Equation: $y=x(x-2)$

$\implies x(x-2)=0$

$\implies x=0$

$\implies (x-2)=0 \implies x=2$

Therefore, the x-intercepts are x = 0 and x = 2

The midpoint of the x-intercepts is x = 1, so the x-coordinate of the vertex is x = 1

Equation: $y=(x-4)(x+5)$

$\implies (x-4)(x+5)=0$

$\implies (x-4)=0 \implies x=4$

$\implies (x+5)=0 \implies x=-5$

Therefore, the x-intercepts are x = -5 and x = 4

The midpoint of the x-intercepts is x = -0.5, so the x-coordinate of the vertex is x = -0.5

Equation: $y=-5x(3-x)$

$\implies -5x(3-x)=0$

$\implies -5x=0 \implies x=0$

$\implies (3-x)=0 \implies x=3$

Therefore, the x-intercepts are x = 0 and x = 3

The midpoint of the x-intercepts is x = 1.5, so the x-coordinate of the vertex is x = 1.5

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

4 0

2 years ago

The circle passes through the point (-1,8). What is it’s radius? Options: A: 3 B: √8 C: √6 D: 2.75

Jlenok [28]

Answer:

B √8

Step-by-step explanation:

Equation of a circle is:

(x − h)² + (y − k)² = r²

where (h, k) is the center and r is the radius.

The center of the circle is (1, 6).

(x − 1)² + (y − 6)² = r²

The circle passes through the point (-1, 8).

(-1 − 1)² + (8 − 6)² = r²

4 + 4 = r²

r = √8

8 0

4 years ago