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galben [10]
2 years ago
7

Determine two angles between 0° and 360° that have a cosine of negative root3/2 without using a calculator

Mathematics
1 answer:
Naily [24]2 years ago
5 0

Answer:

150° and 210°

Step-by-step explanation:

1) to drow a circle with radius=1 in the system of coordinates like in the attached picture;

2) to mark point (-√3/2)≈-0.866 on X-axis (in the picture it is the point M);

3) to graph line AB through point M, the line AB || Y-axis and the points A and B are on the circle with radius=1;

4) to measure the angles ∠ROA and ∠ROB (the points are marked with red colour);

5) finally, m(∠ROA)=150°; m(∠ROB)=210°.

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I WILL AWARD BRAINLIEST!!!! PLEASE HELP!!!!!
Dahasolnce [82]

as AB || DE then

angle BAE = angle AED

so angle AED = 70

as AD = AE then

angle AED = angle ADE = 70

now in a triangle

angle DAE + Angle ADE + angle AED = 180

angle DAE + 70 + 70 = 180

angle DAE = 180 - 140 = 40

4 0
3 years ago
PLEASE HELP!!!
riadik2000 [5.3K]
The answer is a if the line is dotted/dashed. The answer is c if the line isn't dotted/dashed.
7 0
2 years ago
Read 2 more answers
Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent. How many text messag
professor190 [17]

Given that Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent.

Kimora's cell phone bill for one month is $52.

We need to determine the number of text messages Kimora sent for one month.

Also, we need to write and equation and solve it.

<u>The equation:</u>

Let x denote the number of text messages Kimora sent for one month.

Thus, the equation is given by

35+0.05x=52

Therefore, the equation for the number of text messages Kimora sent for one month is 35+0.05x=52

<u>Solving the equation:</u>

We need to solve the equation 35+0.05x=52

Subtracting both sides of the equation by 35, we get;

0.05x=17

Dividing both sides of the equation by 0.05, we get;

x=340

Therefore, the number of messages sent is 340.

3 0
3 years ago
Types of bonds are divided into three categories: good risk, medium risk, and poor risk. Assume that of a total of 11, 332 bonds
Alekssandra [29.7K]

Answer:

Probabilty of not poor= 0.75

Step-by-step explanation:

total of 11332 bonds.

7311 are good risk.

1182 are medium risk.

Poor risk

= total risk-(good risk+ medium risk)

= 11332-(7311+1182)

= 11332-8493

= 2839.

Poor risk = 2839

Probabilty that the ball choosen at random is not poor= 1 - probability that the ball is poor

Probability of poor = 2839/11332

Probabilty of poor= 0.2505

Probabilty that the ball choosen at random is not poor= 1- 0.2505

= 0.7495

To two decimal place= 0.75

3 0
3 years ago
One estimate of the population of the world on January 1, 2005, is
inn [45]

Answer:

8,566,379,470 people

Step-by-step explanation:

Let's start simple.  In order to find the population increase on January 1, 2006, we need to multiply 6,486,915,022 by 1.4% and add it to 6,486,915,022.

  1. 6,486,915,022*1.4% = 90,816,810.308
  2. 90,816,810.308+6,486,915,022 = 6,577,731,832.31 people on January 2006.

Note that the above two steps gives the same answer as 6,486,915,022*1.014.

So we need to do this for each year.  20 years pass between 1/1/2005 and 1/1/2025.  

We need to do 6,486,915,022*1.014*1.014*1.014... 20 times.

This is equivalent to 6,486,915,022*1.014^{20}.

Multiplying it out gives us 8566379470.2 = 8,566,379,470 people.

4 0
3 years ago
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