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3 years ago

Ann and Pat have 3 cupcakes to share. They cut each cupcake into 2 equal parts.

Mathematics

2 answers:

andrew11 [14]3 years ago

6 0

3/1 divide by 1/2 =6
Remember when you divide fractions you keep the first number the same , change the division sign to multiplication sign and flip the second fraction like this
3/1 x 2/1=6

Rama09 [41]3 years ago

3 0

Answer:

Step-by-step explanation:

3+3 maybe :) .

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How do you change 36/10 to a decimal?

Elina [12.6K]

Divide 36 by 10
36/10=3.6

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3 years ago

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There are 130 people in a sport centre.

Mashcka [7]

Answer:

Step-by-step explanation:

Using set notation to answer the question. let:

n(U) be the total people in a sport centre =130

n(G) be number of people that use the gym. = 76

n(P) be number of people that use the swimming pool. = 60

n(T) be number of people that use the track = 32

n(G∩P) be number of people that uses the gym and the pool = 23

n(P∩T) be number of people that uses the pool and the track = 8

n(G∩T) be number of people that uses the gym and the track = 320

n(G∩P∩T) be number of people that uses all three facilities = 6

Using the relationship below;

n(U)= n(GUPUT)+n(GUPUT)'

where n(GUPUT)' is the number of people that doesn't use any facility.

Before we can get that, we need to know n(GUPUT) using the formula;

n(GUPUT) = n(G) + n(P)+n(T)-n(G∩P)-n(P∩T)-n(G∩T)+n(G∩P∩T)

n(GUPUT) = 76+60+32-23-8-20+6

n(GUPUT) = 123

n(GUPUT)' = n(U)- n(GUPUT)

n(GUPUT)' = 130 - 123

n(GUPUT)' = 7

This means that 7 person doesn't use any facility.

Probability that a person selected at random doesn't use any facility = n(GUPUT)' /n(U) = 7/130

3 0

3 years ago

The probability of a biased coin landing on heads is 2/7 complete the tree diagram

mamaluj [8]

Answer:

The numbers needed to fill each box are in the image attached

Step-by-step explanation:

The probability of the coin landing on heads is 2/7, so the probability of it landing on tails is 1 - 2/7 = 5/7

The probability of landing heads 2 times is:

P = (2/7) * (2/7) = 4/49

The probability of landing heads and then tails is:

P = (2/7) * (5/7) = 10/49

The probability of landing tails and then heads is:

P = (5/7) * (2/7) = 10/49

The probability of landing tails 2 times is:

P = (5/7) * (5/7) = 25/49

The numbers needed to fill each box are in the image attached.

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3 years ago

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Solve for x: −34x−1=115 .

krek1111 [17]

Answer:

x = - $\frac{64}{45}$

Step-by-step explanation:

- $\frac{3}{4}$ x - 1 = $\frac{1}{15}$

add 1 to both sides:

- $\frac{3}{4}$ x = $\frac{16}{15}$

multiply both sides by 4:

-3x = $\frac{64}{15}$

divide both sides by -3:

x = - $\frac{64}{45}$

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Fantom [35]

Answer:2 I thinkkk

Step-by-step explanation:

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