Ana tiene 14 años menos que Beto y ambas edades suman 56 años

Three horses, call them a, b, and c, are going to race against each other. the probability that a will win the race is 1⁄5 and t

Genrish500 [490]

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6 0

2 years ago

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

2 years ago

(x ÷ 8) + 23 – 4 = 36

kifflom [539]

Answer:

(x ÷ 8) + 23 – 4 = 36

x = 136

Step-by-step explanation:

3 0

1 year ago

If 120% is £360 what is 100%

AleksAgata [21]

In this question a vital information has been provided. This information can be used for determining the answer to the question that is asked. It is given that 120% of a certain number is 360 pound. The 100% value of the number needs to be determined.
Let us assume the number to be = x
Then
120x/100 = 360
12x/10 = 360
12x = 360 * 10
12x = 3600
x = 3600/12
= 300
Now we can say that the 100% of the number or the actual number is 300 pounds. I hope the problem is clear to you and you can understand the trick involved in the question.

6 0

2 years ago

Help, please! If possible explain it like your talking to a little kid :) Thank you♡

monitta

Answer:

GCF: y³z³

Step-by-step explanation:

The greatest common factor is the a term that you can take out of all the terms given to you. This term, when multiplied to each of the individual numbers in the set, will return you to the original amount.

In this case, note that they all share the variables y and z, and that each of them have <em>at least</em> 3 y's and 3 z's. For you to factor, you will divide these from all the terms.

$\frac{x^{3}y^{5}z^{5} , y^{3}z^{5} , xy^{3}z^{3} }{y^{3}z^{3}} = x^{3}y^{2}z^{2} , z^{2} , x$

y³z³(x³y²z² , z² , x)

~

7 0

2 years ago