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rjkz [21]
3 years ago
11

-3/2 +1/3 =me ayudan plis ​

Mathematics
1 answer:
const2013 [10]3 years ago
5 0

Answer:

-7/6

Step-by-step explanation:

First convert the fractions so you should have -9/6 and 2/6.

Then add them together and you should get -7/6.

You might be interested in
Line segment L N is tangent to circle O at point M and QM is a diameter.
Oksana_A [137]

Answer:

The measure of ∠QML is 90°

The measure of ∠PMN is 117°

Step-by-step explanation:

In circle O:

  • MQ is a diameter
  • LN is a tangent to circle O at point M
  • PM and RQ are secants
  • m∠PMO is 27°
  • m∠MQR is 42

∵ MQ is a diameter of circle O

∵ LN is a tangent to circle O at point M

- A diameter is perpendicular to a tangent at the point of

 contact between them (one of end-point of the diameter)

∴ QM ⊥ LN at point M

∴ m∠QML = m∠QMN = 90°

The measure of ∠QML is 90°

∵ m∠PMN = m∠PMO + m∠QMN

∵ m∠PMO = 27° ⇒ given

∵ m∠QMN = 90° ⇒ proved

∴ m∠PMN = 27 + 90

∴ m∠PMN = 117°

The measure of ∠PMN is 117°

5 0
4 years ago
Read 2 more answers
Graph the function y = |8 - 2x| + 3. Which is a point on the function? (6.2, 7.4) (7.8, 11.2) (8.6, 6.8) (9.6, 7.3)
Fiesta28 [93]
For this case we have the following function:
 y = | 8 - 2x | + 3

 The first thing you should do is graph the function to see the behavior.
 When observing the graph (in the attached image) we observe that the following point belongs to the graph:
 (6.2, 7.4)

 To prove it, let's evaluate the point in the function:
 7.4 = l 8 - 2 (6.2) l + 3

7.4 = l 8 - 12.4 l + 3

7.4 = l -4.4 l + 3

7.4 = 7.4
 The equation is fulfilled and therefore the point belongs to the graph.
 Answer:
 
(6.2, 7.4)
 
See attached image

8 0
3 years ago
HELP PLEASE THIS IS IMPORTANT!! (please show work too)
SashulF [63]

Answer:

D    2(x + 3)(x - 3)

Step-by-step explanation:

2x^{2}  - 18

= 2(x^{2}  - 9)   Factor out the greatest common factor of 2

= 2(x + 3)(x - 3)   Factor the difference of 2 squares

8 0
3 years ago
Jada bikes 2 miles in 12 minutes.
drek231 [11]
A 1/6 miles per minute
6 0
3 years ago
Read 2 more answers
Which hyperbola’s asymptote rectangle has the greatest perimeter?
Vitek1552 [10]

Answer:

The greatest perimeter is in (D) ⇒ the perimeter = 60 units

Step-by-step explanation:

* In the hyperbola

- The standard form of the equation of a hyperbola with

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

∵ the length of the transverse axis is  2a

∵ the length of the conjugate axis is  2b

∴ The perimeter of asymptote rectangle is 2(2a + 2b)

* Lets check the answers to find the greatest perimeter

A) (x - 4)²/11² - (y + 2)²/3² = 1

* Compare it with the standard form equation

∵ a = 11 ⇒ 2a = 22

∵ b = 3 ⇒ 2b = 6

∴ The perimeter = 2(22 + 6) = 56

B) (x - 2)²/4² - (y + 1)²/10² = 1

* Compare it with the standard form equation

∵ a = 4 ⇒ 2a = 8

∵ b = 10 ⇒ 2b = 20

∴ The perimeter = 2(8 + 20) = 56

C) (x + 5)²/5² - (y - 3)²/9² = 1

* Compare it with the standard form equation

∵ a = 5 ⇒ 2a = 10

∵ b = 9 ⇒ 2b = 18

∴ The perimeter = 2(10 + 18) = 56

D) (x - 7)²/8² - (y - 2)²/7² = 1

* Compare it with the standard form equation

∵ a = 8 ⇒ 2a = 16

∵ b = 7 ⇒ 2b = 14

∴ The perimeter = 2(16 + 14) = 60

* The greatest perimeter is in (D)

4 0
3 years ago
Read 2 more answers
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