Plz help with this question and explain

Mathematics

1 answer:

alekssr [168]2 years ago

5 0

I see two lines. The degree measure of any line is 180°.

4y + 5y = 180°

9y = 180°

y = 180°/9

y = 20

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4x – 8 = 12<br> 4x - 8 + 8 = 12 + 8<br> 4x = 20<br> 20<br> h

iogann1982 [59]

X=5, if that’s what you’re solving for

6 0

2 years ago

A company produces birthday cards and get well cards at a ratio of 6 to 5 how many birthday cards can ve expected if 60 get well

Alik [6]

The number of birthday cards made is 72.

<h3>Description of ratios</h3>

Ratio expresses the relationship between two numbers. It shows the frequency of the number of times that one value is contained in another number. The sign used to represent ratios is :

<h3>Determining the total cards made. </h3>

Total card = (sum of ratios x number of get well cards) / ratio of get well cards

(11 x 60) / 5 = 132

<h3>Number of birthday cards made </h3>

6/11 x 132 = 72 cards

To learn more about ratios, please check: brainly.com/question/25927869

4 0

2 years ago

In a random sample, 10 students were asked to compute the distance they travel one way to school to the nearest tenth of a mile.

elixir [45]

Answer:

Mean = 3.12, Variance = 3.324, Standard deviation = 1.8232

Step-by-step explanation:

Total number of students = 10 students.

Given data, 1.1, 5.2, 3.6, 5.0, 4.8, 1.8, 2.2, 5.2, 1.5, 0.8

To find the mean, at first we have to take the sum of all given data and then divide with the number of students.

Let the data is X, = 1.1, + 5.2, + 3.6, + 5.0, + 4.8, + 1.8, + 2.2, + 5.2, + 1.5, + 0.8 = 31.2

Mean = 31.2 / 10 = 3.12

$\text{Standard deviation, S} = \sqrt{\frac{\sum x^{2} - \left [ (\sum x)^{2}/n \right ]}{n-1}} \\S = 1.8232 \\\rm The \ Variance = S^{2} = 3.324$

5 0

2 years ago

Round to the nearest hundredth (Geometric Series problem)

WITCHER [35]

Answer:

15.98

Step-by-step explanation:

∑₁¹⁰ $8(\frac{1}{4} )^{n-1}$

$=8[1+\frac{1}{4} +\frac{1}{16} + ........ +t_{10}]$

We have to use the formula of sum of a G.P. series with common ratio r < 1.

If the first term is a, the common ratio is r and the number of terms is n then the sum [a + ar + ar² + ar³ + ......... up to n terms] is given by

$[a \times\frac{1-r^{n} }{1-r}]$