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Veronika [31]
3 years ago
13

Graph the circle x2 + y2 – 2x – 80 = 0

Mathematics
1 answer:
vfiekz [6]3 years ago
5 0

x2+y2−2x−80=0

Write the problem as a mathematical expression.x2+y2−2x−80=0

Add  80 to both sides of the equation. x2+y2−2x= 80 Complete the square for x2− 2x. Tap for more steps...(x−1)2−1 Substitute  (x−1)2−1 for x−2x in the equation  x2+y2−2x =80 .(x−1)2−1+y2=80 Move −1 to the right side of the equation by adding  1 to both sides.(x−1)2+y2=80+1Add 80 and 1.(x−1)2+y2=81

This is the form of a circle. Use this form to determine the center and radius of the circle.(x−h)2+(y−k)2=2Match the values in this circle to those of the standard form. The variable r represents the radius of the circle, h represents the x-offset from the origin, and  k represents the y-offset from origin.r=9h=1k=0 The center of the circle is found at (h,k). Center: (1,0)These values represent the important values for graphing and analyzing a circle. Center: (1,0)Radius:  9

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How many times does 6 go into 22
sergeinik [125]
Hey!

We can use long division to solve this,
Let's write it.
6\overline{|\smallspace22}\space\space\space\space
Then, divide 22 by 6 to get 3.
\begin{matrix}\space\space\space\space\space\space\emptyspace3\space\space\space\space\space\space\space\space\space\space\space\space\\ 6\overline{|\smallspace22}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}
Multiply the quotient by the divisor...
\begin{matrix}\space\space\space\space\space\space\emptyspace3\space\space\space\space\space\space\space\space\space\space\space\space\\ 6\overline{|\smallspace22}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\underline{\emptyspace1\emptyspace8}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}
Subtract 18 from 22.
\begin{matrix}\space\space\space\space\space\space\emptyspace3\space\space\space\space\space\space\space\space\space\space\space\space\\ 6\overline{|\smallspace22}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\underline{\emptyspace1\emptyspace8}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\space\space\emptyspace4\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}
As you can see, our answer using long division would be 3 with a remainder of 4. 

Thanks!
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