Question

What are all the real zeros

Answer 1

For this case we have a function of the form $y = f (x)$, where$f (x) = (x-12) ^ 3-10$

To find the real zeros we must equal zero and clear the variable "x".

$(x-12) ^ 3-10 = 0$

We add 10 to both sides of the equation

$(x-12) ^ 3-10 + 10 = 10\\(x-12) ^ 3 = 10$

We apply cube root to both sides of the equation:

$\sqrt[3]{(x-12)^3} = \sqrt[3] {10}\\x-12 = \sqrt[3] {10}$

We add 12 to both sides of the equation:

$x-12 + 12 = \sqrt[3] {10} +12\\x = \sqrt[3] {10} +12$

Answer:

Option D