Write the nth term of the following sequence in terms of the first term of the sequence.

Mathematics

1 answer:

ZanzabumX [31]2 years ago

6 0

Answer:

a(n) = 1 + 7(n-1)

Step-by-step explanation:

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Evaluate 5 + 3x for (a) x= -2 and (b)x= 3. Write your answers in simplest form.

Alisiya [41]

Answer:

i really do not know the answer

5 0

2 years ago

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1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

2 years ago

The coordinate point F(-8, 0) after a dilation with scale factor of 0.25, centered at the origin, becomes the point

FrozenT [24]

Answer:

$(-2,\, 0)$ .

Step-by-step explanation:

Dilate a point $(x,\, y)$ by a scale factor of $r$ with $(a,\, b)$ as the center, and the resultant point would be at $(a + r\, (x - a),\, b + r\, (y - a))$ .