$\pi+18-irrational\ because\ \pi\ is\ irrational\\\\\sqrt{25+1.75}=\sqrt{26.75}=\sqrt{\dfrac{2675}{100}}=\dfrac{\sqrt{2675}}{\sqrt{100}}=\dfrac{\sqrt{25\cdot107}}{10}\\\\=\dfrac{\sqrt{25}\cdot\sqrt{107}}{10}=\dfrac{5\sqrt{107}}{10}=\dfrac{\sqrt{107}}{2}-irrational\\\\\sqrt{3+5.5}=\sqrt{8.5}=\sqrt{\dfrac{85}{10}}=\sqrt{\dfrac{850}{100}}=\dfrac{\sqrt{850}}{\sqrt{100}}=\dfrac{\sqrt{25\cdot34}}{10}\\\\=\dfrac{\sqrt{25}\cdot\sqrt{34}}{10}=\dfrac{5\sqrt{34}}{10}=\dfrac{\sqrt{34}}{2}-irrational$

$\pi+\sqrt2-irrational$

3 0

3 years ago

Solve the following equation for x to find the total number of people who became members of a social networking site for a certa

ra1l [238]

X-0.8x=72
0.2x=72 /0.2
X = 360

3 0

3 years ago

PLEASE HELP

Maslowich

If an event occurs 0 times (out of 4, in this case) then it does not occur at least once. So we can find the probability of it not occurring and then subtract that value from 1.

So, what are the chances of it not occurring in 1 trip?

1−.37=.63

What about not occurring in 2 trips?

(1−.37)⋅(1−.37)=.63⋅.63=.3969

Now what about not occurring in 4 trips?

.63^4 = 0.15752961

We must subtract this value from 1

(recall that what we just calculated is the probability of it not occurring, so the probability of it occurring at least once is:

1−0.15752961 = .84247039

TLDR - In 4 trips the chance of a guest catching a cutthroat once in under 4 trips in 0.84.

8 0

3 years ago

Please help i will mark brainly!

mariarad [96]

Answer:

D is the answer. :)

8 0

3 years ago

What is the output of the expression 14/3​

What is the output of the expression 14/3