What is the output of the expression 14/3

cos60=5/zy ??? how do I get rid of the 5? Normally I would multiply by the denominator but that doesn't work here. The end answe

saw5 [17]

cos 60 = 1/2

1/2 = 5/zy

1= 10/zy

zy=10

8 0

2 years ago

How long will it take to drive 200 miles if the driver's average speed is 55 mph?

ladessa [460]

We'll be looking for time here.

s=d/t

ts=d

t=d/s

------------------------

Average speed is:

s=(55m)/h

Distance is:

200m

---------------------------

t=(200m)/(55m/h)

t=(200m/1)*(h/(55m))

t=200/55*h

t≈3.64 hours

4 0

3 years ago

Read 2 more answers

Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

Definition

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

Definition II

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

Examples

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

Absolute Value Property I

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

Conclusion

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

2 years ago

Read 2 more answers

7. On Saturday, a craft store had 150 visitors, and 80% of the visitors made a purchase. Of the customers who made a purchase, 3

torisob [31]

Answer:

24 customers bought 3+ items.

Step-by-step explanation:

80% of 150 = 120

39/120 bought 1 item

57/120 bought 2 items

39 + 57 = 96

120 - 96 = 24

24 customers bought 3+ items.

Hope this helps! :)

8 0

3 years ago

The width of a rectangle is 2 less than twice its length. If the area of the rectangle is 110

yanalaym [24]

Answer:

Use the formula of areal*b*h

3 0

3 years ago

What is the output of the expression 14/3​

What is the output of the expression 14/3