The valid exclusion of the algebraic fraction is (c) a =0, b =0, a =2b
<h3>How to determine the valid exclusion?</h3>
The expression is given as:
8ab^2x/4a^2b - 8ab^2
Set the denominator to 0
4a^2b - 8ab^2 = 0
Divide through by 4ab
a - 2b = 0
Add 2b to both sides
a = 2b
Hence, the valid exclusion of the algebraic fraction is (c) a =0, b =0, a =2b
Read more about algebraic fraction at:
brainly.com/question/4344214
#SPJ1
<h3>Answers:</h3>
- Congruent by SSS
- Congruent by SAS
- Not congruent (or not enough info to know either way)
- Congruent by SAS
- Congruent by SSS
- Not congruent (or not enough info to know either way)
- Congruent by SAS
- Congruent by SAS
==================================
Explanations:
- We have 3 pairs of congruent sides. The tickmarks tell us how the congruent sides pair up (eg: the double tickmarked sides are the same length). So that lets us use SSS. The shared overlapping side forms the third pair of congruent sides.
- We have two pairs of congruent sides (the tickmarked sides and the overlapping sides), and an angle between the sides mentioned. Therefore, we can use SAS to prove the triangles congruent.
- We don't have enough info here. So the triangles might be congruent, or they might not be. The convention is to go with "not congruent" until we have enough evidence to prove otherwise.
- We can use SAS like with problem 2. Vertical angles are always congruent.
- This is similar to problem 1, so we can use SSS here.
- There isn't enough info, so it's pretty much a repeat of problem 3
- Same idea as problem 4.
- Similar to problem 2. We have two pairs of congruent sides and an included angle between them allowing us to use SAS
The abbreviations used were:
- SSS = side side side
- SAS = side angle side
The order is important with SAS because the angle needs to be between the sides mentioned.
Answer:
lol they give you the slope and the intercept
Step-by-step explanation:
slope is 72, y int is 8
Answer:
y =4x-6
Step-by-step explanation:
first we have to find the gradient,m
m= y2-y1/x2-x1
= 6-2/3-2
= 4/1
=4
equation : y=mx+c , m=4 , (2,2) [you have only take one point either (2,2) or (3,6) is up to you ;) ]
so , sub the point and gradient into y=mx+c:
2=4(2)+c
2=8+c
2-8=c
-6=c
c=-6
In the end , y =4x-6
hope this help you!! ;)))
Answer:
0.070198..
Step-by-step explanation: its an on going number so make sure to put the line on top on the 0198