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Mkey [24]
3 years ago
15

A 10.0kg rock is dropped and hits the ground below at a speed of 60 m/s . Calculate the gravitational potential energy of the ro

ck before it was dropped
Mathematics
1 answer:
disa [49]3 years ago
7 0

Answer:

Solution:

Mass of body, m= 10kg

velocity, v= 60m/s

Now,kinetic energy on earth= potential energy at a that point [energy conservation]

so, kinetic energy= 1/2*m* v^2

= 1/2* 60(60)^2

= 30* 60*60

= 108000 joules

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Answer:

x is form

Step-by-step explanation:

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Which expression is equivalent to 12a⁻⁴ b³c⁸/3a⁻² b⁹c⁻²
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Oh me being also confused
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Is 5 1/2 in the set of integers, whole numbers, both or neither
SCORPION-xisa [38]
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?
yanalaym [24]

Answer:

A=\pi \frac{d^2}{4}

Step-by-step explanation:

The typical equation for the area of a circle is A=\pi r^2. Since the answer choices are in terms of <em>d</em>, the diameter of the circle, you will need to find <em>r</em> in terms of <em>d</em>.

To find <em>r</em> in terms of <em>d</em>, you know that the diameter of a circle is two times its radius. As an equation, this is

d=2r, or solving for <em>r</em>,

r = \frac{d}{2}.

Now that you have an equation for <em>r</em> in terms of <em>d, </em>you can substitute <em>r</em> with \frac{d}{2} from the original equation.

A=\pi r^2

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4 0
3 years ago
A. Find PR in the diagram <br> b. Find the perimeter of quadrilateral PQRS
Elan Coil [88]

Answer:

Step-by-step explanation:

The quadrilateral has 4 sides and only two of them are equal.

A) to find PR, we will consider the triangle, PRQ.

Using cosine rule

a^2 = b^2 + c^2 - 2abcos A

We are looking for PR

PR^2 = 8^2 + 7^2 - 2 ×8 × 7Cos70

PR^2 = 64 + 49 - 112 × 0.3420

PR^2 = 113 - 38.304 = 74.696

PR = √74.696 = 8.64

B) to find the perimeter of PQRS, we will consider the triangle, RSP. It is an isosceles triangle. Therefore, two sides and two base angles are equal. To determine the length of SP,

We will use the sine rule because only one side,PR is known

For sine rule,

a/sinA = b/sinB

SP/ sin 35 = 8.64/sin110

Cross multiplying

SPsin110 = 8.64sin35

SP = 8.64sin35/sin110

SP = (8.64 × 0.5736)/0.9397

SP = 5.27

SR = SP = 5.27

The perimeter of the quadrilateral PQRS is the sum of the sides. The perimeter = 8 + 7 + 5.27 + 5.27 = 25.54 cm

6 0
3 years ago
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