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3 years ago

11

Find the difference of the two expressions. (2/5 x + 5) - (1/5 x - 3)

2 answers:

ehidna [41]3 years ago

5 0

8+x/5 Hope I helped !!!

makkiz [27]3 years ago

4 0

8+x/5 hope you like beans

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Whats this i have been struggling for this . 5(3x−2)=−x−10

Inessa05 [86]

Answer:

$x=0$

Step-by-step explanation:

$5(3x-2)=-x-10~(Given)\\\\15x-10=-x-10~(Distribute~5~to~3x-2)\\\\15x-10+x=-x-10+x~(Add~x~on~both~sides)\\\\16x-10=-10~(Simplify)\\\\16x-10+10=-10+10~(Add~10~on~both~sides)\\\\16x=0~(Simplify)\\\\\frac{16x}{16}=\frac{0}{16}~(Divide~16~on~both~sides)\\\\x=0~(Simplify)$

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2 years ago

What is equivalent to (73)–2

mario62 [17]

Answer:

71

Step-by-step explanation:

(73)-2 is equivalent to 71

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2 years ago

Read 2 more answers

Bobs supermarket sells red apples and green apples at the ratio of 5:3.

nika2105 [10]

Answer:

10 red apples and 6 green apples

Step-by-step explanation:

first you multiply 5×2 to get 10 apples

then you multiply 3×2 to get 6 apples

5 0

3 years ago

Can someone help me w questions 1 and 2 i’ll give u brainliest

Leni [432]

Answer:

1. x^2+5

2.x^2-6x+9

Step-by-step explanation:

these are just translations up and to the right.

since the f(x)=x^2

the transformations would be

1. g(x)=x^2+5

2.g(x)=(x-3)^2 = x^2-6x+9

4 0

2 years ago

On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John

insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

$H_{max}=\frac{v^2}{2g}$

$H_{max} = \frac{(48)^2}{2 \times 12}$

= 96 ft

b). Time he can stay in the air before hitting the ground is

$T=\frac{2v}{g}$

$T=\frac{2 \times 48}{12}$

= 8 seconds

c). Considering upward motion as positive direction.

v = u + at

We find the time taken to reach the maximum height by taking v = 0.

v = u + at

0 = 16 + (12) t

$t=\frac{16}{12}$

$=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t = $=\frac{4}{3} \ s$ , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$ feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0

3 years ago