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antoniya [11.8K]

3 years ago

5

Please answer correctly I’ll mark you after if it’s correct

1 answer:

Inessa [10]3 years ago

3 0

Answer:

-32

Step-by-step explanation:

its going back in 8 so 8 ×4=32

-32=answer

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What is the value of x?

joja [24]

6x+6x+8x=180
20x=180
x=9

5 0

3 years ago

David lays bricks at a rate of 40 brick per hour.if he has a large job laying 2,400 bricks, how many hours will it take him to f

Alex787 [66]

Answer:

Step-by-step explanation:

60 hours for entire job

divided by 8 hours per day 7 1/2 days

3 0

3 years ago

the terminal side of an angle in standard position rotated one-sixth of a revolution counterclockwise from the positive x-axis.

emmasim [6.3K]

Answer:

60 degrees and pi/3 radians

Step-by-step explanation:

A full revolution is 360° or 2pi

… so multiply by 1/6 to get 60° and pi/3 radians

5 0

4 years ago

Find all solutions to the equation in the interval [0,2pi). Enter the solutions in increasing order. Cos 2x = cos x

goblinko [34]

Step-by-step explanation:

$\cos(2x) = \cos(x)$

$\cos {}^{2} (x) - \sin {}^{2} (x) = \cos(x)$

$\cos {}^{2} (x) - (1 - \cos {}^{2} (x) ) = \cos(x)$

$2 \cos {}^{2} (x) - 1 = \cos(x)$

$2 \cos {}^{2} (x) - \cos(x) - 1 = 0$

$2 \cos {}^{2} (x) - 2 \cos(x) + \cos(x) - 1 = 0$

$2 \cos(x) ( \cos(x) - 1) + 1( \cos(x) + 1)$

$(2 \cos(x) + 1)( \cos(x) - 1) = 0$

$2 \cos(x) + 1 = 0$

$2 \cos(x) = - 1$

$\cos(x) = - \frac{1}{2}$

$x = \frac{2\pi}{3} ,x = \frac{4\pi}{3}$

$\cos(x) - 1 = 0$

$\cos(x) = 1$

$x = 0$

So our answer are

$0, \frac{2\pi}{3} , \frac{4\pi}{3}$

4 0

2 years ago

Please be quick! i need answer for each in the box, giving 15 points

Anastaziya [24]

The solutions are $f(-2)=12, f(-1)=7, f(0)=2, f(1)=-3$ and $f(2)=-8$

Explanation:

To find the values of f(x), we need to substitute the values for x in the function $f(x)=2-5x$

For $x=-2$ ,

$\begin{aligned}f(x) &=2-5 x \\&=2-5(-2) \\&=2+10 \\&=12\end{aligned}$

Thus, $f(-2)=12$

For $x=-1$ ,

$\begin{aligned}f(-1) &=2-5(-1) \\&=2+5 \\&=7\end{aligned}$

Thus, $f(-1)=7$

For $x=0$ ,

$\begin{aligned}f(0) &=2-5(0) \\&=2+0 \\&=2\end{aligned}$

Thus, $f(0)=2$

For $x=1$ ,

$\begin{aligned}f(1) &=2-5(1) \\&=2-5 \\&=-3\end{aligned}$

Thus, $f(1)=-3$

For $x=2$ ,

$\begin{aligned}f(2) &=2-5(2) \\&=2-10 \\&=-8\end{aligned}$

Thus, $f(2)=-8$

Hence, the solutions are $f(-2)=12, f(-1)=7, f(0)=2, f(1)=-3$ and $f(2)=-8$

7 0

3 years ago