Answer:
hih;ihih h
Step-by-step explanation:
ih ;ih ihih;h
Answer:
1
Step-by-step explanation:
1/(1+p+q^-1)+1/(1+q+r^-1)+1/(1+r+p^-1) = 1.
The domain are all valid values for x (the independent variable) that can be used in an equation.
We have to look at any potential values of x which won't work. Easily put: in algebra, just look for values of x which cause either division by zero, or the square root of negative numbers.
A couple of examples:
y=2x+4
You can insert any negative or positive value, or zero, for x and get a valid equation. Therefore the domain is the set of all real numbers. Answers are usually written as:
x: {R}, or simply 'all real numbers'.
what about y=2/(x-1)
In this equation, x appears in the denominator. If x-1=0, then division by zero would occur.
Solve: x-1≠0
x≠1
In set notation:
x: (-∞,1)∪(1,∞)
Parentheses are next to the 1, as the domain comes up to 1, but does not include 1.
Read left to right, the domain is "negative infinity to 1, exclusive, in union with 1 to positive infinity"
Answer:
If corresponding vertices on an image and a preimage are connected with line segments, the line segments are divided equally by the line of reflection. That is, the perpendicular distance from the line of reflection to either of the corresponding vertices is the same. Line is a perpendicular bisector of the connecting line segments.
Step-by-step explanation:
