All categories

3 years ago

Tricia is managing tasks that have been assigned to her. She needs to enter mileage information in relation to a

Computers and Technology

2 answers:

Lady bird [3.3K]3 years ago

6 0

Answer:

Task

Explanation:

hram777 [196]3 years ago

3 0

Answer:

I'm not sure but I think It may be D:Send Status Report

Explanation:

Unit test on edg 2021

You might be interested in

Which of the following is true of two-factor authentication?

dybincka [34]

Answer: D)It relies on two independent proofs of identity.

Explanation: Two factor authentication is technique which uses two steps/stage for the verification or authentication.It is done for the extra security maintenance.IT is also known as 2FA. It consist of two different authentication component so that it penetrates through double protection layer .

Other options are incorrect because It RSA public key cannot be used for the authentication of private content. It does not use both hand geometry at same time for both the levels and It does not utilize only single sign-on technology. Thus, the correct option is option(D).

7 0

3 years ago

Which best describes what databases do?

quester [9]

Answer:

They create categories for data.

Explanation:

They can create categories for data, by storing the data. Information itself can be stored in multiple ways, like creating categories!

I hope this helped :)

6 0

3 years ago

Read 2 more answers

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago

Consider the following statements. An abstract class is better than an interface when the variables in the abstract class or int

Ksivusya [100]

Well the nonchalant question given for 4th grade red named babyface Justin and Jerome

4 0

2 years ago

By default, after how much time has elapsed in a client's DHCP lease will the client attempt to renew the lease?

maw [93]

The client will attempt to renew halfway through the time of the lease.

3 0

3 years ago