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Anika [276]
2 years ago
9

UPS or FedEx plays what role in the supply?

Computers and Technology
1 answer:
nikdorinn [45]2 years ago
8 0

Explanation:

the answer in the image above

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Read 2 more answers
For this question you must write a java class called Rectangle and a client class called RectangleClient. The partial Rectangle
polet [3.4K]

Answer:

Java.

Explanation:

public class Rectangle {

   private int x;

   private int y;

   private int width;

   private int height;

   ///////////////////////////////////////////////////////////

   public Rectangle(int inX, inY, inWidth, inHeight) {

       x = inX;

       y = inY;

       width = inWidth;

       height = inHeight;

   }

   ///////////////////////////////////////////////////////////

   public int getX() {

       return x;

   }

   public int getY() {

       return y;

   }

   

   public int getWidth() {

       return width;

   }

   public int getHeight() {

       return height;

   }

   ///////////////////////////////////////////////////////////

   public int getArea() {

       return width * height;

   }

   public bool isSquare() {

       if (width == height) {

           return true;

       }

       else

           return false;

   }

   ///////////////////////////////////////////////////////////

   public String toString() {

       return "Rectangle located at (" + x + "," + y + ")" + "with dimensions " + width + "x" + height + "and " + getArea() + "is the area.";

   }

}

8 0
3 years ago
Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive.
puteri [66]

Answer:

import java.util.Scanner;

public class num4 {

   public static void main(String[] args) {

     Scanner in = new Scanner(System.in);

     int sumOdds =0;

     int sumEvens =0;

     int num;

     do{

         System.out.println("Enter positive integers");

         num = in.nextInt();

         if(num%2==0){

             sumEvens+=num;

         }

         else if (num%2!=0){

             sumOdds+=num;

         }

     }while (num>0);

       System.out.println("The sum of evens: "+sumEvens);

       System.out.println("The sum of odds: "+sumOdds);

   }

}

Explanation:

  • Import Scanner class to prompt and receive user input
  • Declare the following variables and initialize them int sumOdds =0, int sumEvens =0, int num;
  • Create a do....while loop That continously prompts user to enter a positive number. The loop should terminate when a negative number is enters (n<=0)
  • Within the while loop use an if condition with the modulo (%) operator to determine even and odd numbers and add to the respective variables
  • Outside of the while loop Print sum of odds and sum of evens

5 0
3 years ago
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