Answer:
an integer between –11 and –10
a whole number between 1 and 2
a terminating decimal between –3.14 and –3.15
Step-by-step explanation:
10 =x
f(x) = x-7
Let f(x) = 3
3 = x-7
Add 7 to each side
3+7 = x-7+7
the 21st day
21 is 3 and 7's least common multiple