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tamaranim1 [39]
3 years ago
7

Solve for w.3w>81.......

Mathematics
1 answer:
AURORKA [14]3 years ago
3 0
I think it’s .2 I could be wrong but just use a calculator.
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Mac's hotel had 128 rooms,and 25% of the rooms in the hotel did not have an ocean view
nata0808 [166]
The answer is 32 rooms did not have an ocean view.

25% = 1/4
( the word of is a keyword that the operation will be multiplication :) )
Knowing this information, the problem is askong 25% times 128.
1/4 x 128= 32
Hope I helped! ♡
7 0
4 years ago
Read 2 more answers
a jet bomber traveling 500 mph arrived over its Target at the same time as its fighter jet escorted which left the same fate 2.5
vlada-n [284]

Since the jet bomber arrived over its Target at the same time as its fighter jet escorted, it took the jet bomber 0.34 h to reach the target.

<h3 />

To find the number of hours, we need to solve simultaneous equations.

<h3>What are simultaneous equations?</h3>

Simultaneous equations are pair of equations which contain two unknowns.

<h3>How to calculate the number of hours the bomber jet took off?</h3>

Let

  • D = distance travelled by both bomber jet and fighter jet.
  • t = time bomber jet took off
  • v = speed of bomber jet.
  • T = time fighter jet took off and
  • V = speed of fighter jet.

So, D = vt

D = 500t  (1)

Also, D = VT

D = 60T  (2)

Since  jet bomber traveling 500 mph arrived over its Target at the same time as its fighter jet escorted which left the same fate 2.5 hours after the bomb took off.

T = t + 2.5

So, D = 60(t + 2.5)  (3)

<h3>The required simultaneous equations</h3>

D = 500t  (1)

D = 60(t + 2.5)  (3)

Equating equations (1) and (3), we have

500t = 60(t + 2.5)

500t = 60t + 150

500t - 60t = 150

440t = 150

t = 150/440

t = 15/44

t = 0.34 h

So, it took the jet bomber 0.34 hours to reach the target.

Learn more about simultaneous equations here:

brainly.com/question/27829171

#SPJ1

8 0
2 years ago
Can someone please help me I reallly need help <br> please help
Serggg [28]

Answer:

c = 38b

Step-by-step explanation:

b = number of boxes

c = total number of cookies.

It is given to you that there are 38 cookies per box. The given equation means that The total number of cookies can be found by multiplying the amount of cookies per box with the amount of boxes in all.

c = 38b is your answer.

~

4 0
3 years ago
I need help with letters (D) and (E). My model equation from letter (C) is: P = -55/4 t+ 340.
IceJOKER [234]

Answer:

(a) The two ordered pairs are (0 , 340) and (4 , 285)

(b) The slope is m = -55/4

The slope means the rate of decreases of the owl population was 55/4

per year (P decreased by 55/4 each year)

(c) The model equation is P = -55/4 t + 340

(d) The owl population in 2022 will be 216

(e)  At year 2038 will be no more owl in the park

Step-by-step explanation:

* Lets explain how to solve the problem

- The owl population in 2013 was measured to be 340

- In 2017 the owl population was measured again to be 285

- The owl population is P and the time is t where t measure the numbers

 of years since 2013

(a) Let t represented by the x-coordinates of the order pairs and P

   represented by the y-coordinates of the order pairs

∵ t is measured since 2013

∴ At 2013 ⇒ t = 0

∵ The population P in 2013 was 340

∴ The first order pair is (0 , 340)

∵ The time from 2013 to 2013 = 2017 - 2013 = 4 years

∴ At 2017 ⇒ t = 4

∵ The population at 2017 is 285

∴ The second order pair is (4 , 285)

* The two ordered pairs are (0 , 340) and (4 , 285)

(b) The slope of any lines whose endpoints are (x1 , y1) and (x2 , y2)

     is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∵ (x1 , y1) is (0 , 340) and (x2 , y2) is (4 , 285)

∴ x1 = 0 , x2 = 4 and y1 = 340 , y2 = 285

∴ m = \frac{285-340}{4-0}=\frac{-55}{4}

* The slope is m = -55/4

∵ The slope is negative value

∴ The relation is decreasing

* The slope means the rate of decreases of the owl population was

  55/4 per year (<em>P decreased by 55/4 each year</em>)

(c) The linear equation form is y = mx + c, where m is the slope and c is

    the value of y when x = 0

∵ The population is P and represented by y

∵ The time is t and represented by t

∴ P = mt + c , c is the initial amount of population

∵ m = -55/4

∵ The initial amount of the population is 340

∴ P = -55/4 t + 340

* The model equation is P = -55/4 t + 340

(d) Lets calculate the time from 2013 to 2022

∵ t = 2022 - 2013 = 9 years

∵ P = -55/4 t + 340

∴ P = -55/4 (9) + 340 = 216.25 ≅ 216

* The owl population in 2022 will be 216

(e) If the model is accurate , then the owl population be be zero after

    t years

∵ P = -55/4 t + 340

∵ P = 0

∴ 0 = -55/4 t + 340

- Add 55/4 t to both sides

∴ 55/4 t = 340

- Multiply both sides by 4

∴ 55 t = 1360

- Divide both sides by 55

∴ t = 24.7 ≅ 25 years

- To find the year add 25 years to 2013

∵ 2013 + 25 = 2038

* At year 2038 will be no more owl in the park

8 0
3 years ago
Can someone please help me with number 19
kipiarov [429]
The expression of the problem is, 8x.
where "x" stands for the number of dogs. so you would then substitute x with 12. Then you would solve the problem to get your answer.(8•12)
3 0
3 years ago
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