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Anarel [89]
3 years ago
9

What is the distance between -6 and 2 on a number line

Mathematics
1 answer:
Likurg_2 [28]3 years ago
7 0
I made a number line and drew it out -6,-5,-4,-3,-2,-1,0,1,2 and i counted how many i had to move over to get to 2 from -6 and i got 8
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laryy has 3 packets of ballons with 15 ballons in each packet. he wants to put the same number of balloons into 10 gift bags wha
wel

larry has 3 packer sin each 15 and total are 45 u wish put in 10 bags then divide 45 by 10 anser is 5

5 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
A model train is 9 centimeters long. The actual engine is 18 meters long. What is the scale of the model? Tracy has a model trai
Umnica [9.8K]

Answer:

1 cm : 2m

1 cm = 2m

118m

Step-by-step explanation:

A scale drawing is a reduced form in terms of dimensions of an original image / building / object

the scale drawing is usually reduced at a constant dimension

scale of the drawing = original dimensions / dimensions of the scale drawing

18 / 9 = 2 : 1

59 x 2 = 118

3 0
3 years ago
How much simple interest does $4,678.00 earn in 529 days at a rate of 7.3%? Round to the nearest cent.
statuscvo [17]

Answer:

$5,172.93

Step-by-step explanation:

We're gonna use the simple interest formula: P = A(1 + r(t))

P = final amount

A = starting amount (4,678)

r = rate (0.073)

t = years (529/365)

P = 4,678(1 + 0.073(529/365))

P = 5,172.9324

7 0
2 years ago
Help please!!
Savatey [412]

Answer:

the pressure decreases. Once it reaches 0 the pressure is 0.

Step-by-step explanation:

you can check this by plugging in values like -0.999 and 0.1 to see

6 0
3 years ago
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