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IgorLugansk [536]

3 years ago

12

Evaluate this expression -2.8 + -2.5

2 answers:

k0ka [10]3 years ago

5 0

Answer:

-5.3

Step-by-step explanation:

-2.8+(-2.5)=-2.8-2.5=-5.3

Nitella [24]3 years ago

4 0

Answer:

-5.3

Step-by-step explanation:

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3. For the function, :c(X)=x^2+4x-5 over x+5<br> (a) Identify the restricted domain value(s).

Mrrafil [7]

Domain is all the possible inputs of an equation. In this example, the only concern is the x + 5 because the denominator cannot equal 0 because we can't divided by 0. So we set x + 5 equal to zero and solve for x.

x + 5 = 0
x = -5
The restriction is that x cannot equal -5.

8 0

3 years ago

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

3 0

3 years ago

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stiv31 [10]

Number 49 is Acute .

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3 years ago

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mel-nik [20]

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3 years ago

A store has apple on sale for $20.00 for 8 pounds. If an apple is approximately 5 ounces, how manyapples can you buy for $120.00

lubasha [3.4K]

Answer: 24 apples

Step-by-step explanation: $20.00 = 8 pounds and 16 ounces = 1 pound So you can do $120.00 divided by 5 = 24 apples

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3 years ago