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Elena-2011 [213]
3 years ago
9

Score: 0 of 2 pts

Mathematics
1 answer:
Alecsey [184]3 years ago
6 0

Answer:

Each state also had a governor. This official was elected either by the legislature or by the citizens. The governor’s job was to carry out the laws. Finally, each state had courts. Judges in the courts decided what the laws meant and how to apply them to each new situation.

Step-by-step explanation:

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5540 in scientific notation
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Answer:

Therefore, the decimal number 5540 written in scientific notation is 5.54 × 103 and it has 3 significant figures.

Step-by-step explanation:

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1 1/6 + 2 2/3 in fraction form
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3 5/6
I think, I haven’t done this in a long time.
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The Sun is v kilometers from the upper edge of the Earth's atmosphere and q kilometers from the surface of the Earth. Which of t
horsena [70]
The distance between the Earth's surface and the upper edge of the Earth's atmosphere would be Q - V.

The distance from the Sun to the Earth is Q. The distance from the Sun to the upper edge of the atmosphere is V. If you subtract V from Q, the remaining distance is that of the Earth's atmosphere.  Q - V = the atmosphere
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Kevin drove 693 miles in 11 hours. At the same rate, how many miles would he drive in 9 hours
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567 Miles

Step-by-step explanation:

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3 years ago
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P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
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