1a. 3^1 / 3^2 = 3^1-2 = 3^-1 = 1/3^1 = 1/3.
2b. 4^2 / 4^4 = 4^2-4 = 4^-2 = 1/4^2.
3c. 6^3/6^5 = 6^3-5 = 6^-2 = 1/6^2.
4d. 3^-5 • 3^2 = 3^-10 = 1/3^10.

I believe for the last question its asking only to rewrite exponent as a positive exponent similar to the first question.

6 0

3 years ago

PLEASE HELP ME I NEED HELP ASAP!!!! PLEASE HELP ON A AND B

valina [46]

Answer:

Step-by-step explanation:

The opposite sides of the rectangle are of equal length.

Therefore we have the system of equations:

$\left\{\begin{array}{ccc}3y=2+x&\text{subtract 2 from both sides}\\3x=2+x+5y&\text{subtract x from both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}3y-2=x&(*)\\2x=2+5y&(**)\end{array}\right$

Substitute from (*) to (**):

$2(3y-2)=2+5y\qquad\text{use distributive property}\\\\(2)(3y)+(2)(-2)=2+5y\\\\6y-4=2+5y\qquad\text{add 4 to both sides}\\\\6y=6+5y\qquad\text{subtract 5y from both sides}\\\\\boxed{y=6}$

Put the value of y to (*):

$x=3(6)-2\\\\x=18-2\\\\\boxed{x=16}$

Calculate the width and the length:

$3x = 3(16) = 48\\\\3y = 3(6) = 18$

The perimeter:

$P = 2w + 2l\\\\P = (48)(18)=864\ in$

8 0

3 years ago

.....................ok​

.....................ok