Answer:
y-intercept is (0,30); x-intercept is (52.5,0).
Step-by-step explanation:
Note that as x increases by 7 from -35 to -28, y decreases by 4 from 18 to 14. Thus, the slope of this line is
m = rise / run = -4/7.
Let's find the equation of the line. Start with the slope-intercept form:
y = mx + b. Use the slope m = -4/7 and the point (-28, 14) to find b:
14 = -(4/7)(28) + b, or
14 = -16 + b. Then b = 30, and the equation of the line in slope-intercept form is y = (-4/7)x + 30. The y-intercept is (0, 30).
Find the x-intercept by setting y=0 and solving the resulting equation for x:
y = (-4/7)x + 30 becomes (4/7)x = 30, and x = (7/4)(30) = 214, or 52.5.
The x-intercept is thus (52.5, 0).
Answer:
20-gon
Step-by-step explanation:
First we start with the formula to find what the sum of angles will be if we know the number of sides.
S=(n-2)*180 where S is the sum of angles and n is the number of sides.
Normally you'd plug in n to find S, but you can do the opposite too.
3240=(n-2)*180
Let me know if you need help working it from here.
Answer:
4....
Step-by-step explanation:
Okay! Free points, uh... 2... and 2... put together... is... four...
In quadratic equations,
a + b = -B
ab = C
where a and b are the roots, B is the second term, and C is the constant.
Substituting,
a + b = -12
ab = 35
The values of a and b from the equation is -7 and -5. Thus, the lesser root is -7.
Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
