Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
Answer:
I think it is 24 cus it's more bigger and cooler and hotter and shorter and butter
P = a + b + c
P = 72
a = x
b = x + 2
c = x + 4
72 = x + x + 2 + x + 4
72 = 3x + 6
72 - 6 = 3x
66 = 3x
66/3 = x
22 = x
x + 2 = 22 + 2 = 24
x + 4 = 22 + 4 = 26
the sides of ur triangle are : 22,24,26 <==
9(2w−y)=21w−9y
First you multiply the numbers in the parenthesis by 9
subtract. 21w-18w=3w
add. -9y+9y=0
divide.
Final answer is 0.
