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liq [111]
3 years ago
7

The fifth grade art class is making quilts

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
5 0

Answer:

how you doing today jasmine

Step-by-step explanation:

nasty-shy [4]3 years ago
3 0

Answer:

trapazoid

Step-by-step explanation:

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Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
3 years ago
What is it yalll !??????
diamong [38]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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Give three points for the equation 9x + 5y = 2 using an XY table and choosing your own values for x, and plot the line.
Elina [12.6K]
X. y

0. 2/5
2/9. 0
3. -5
8 0
3 years ago
fourth,sixth and thirteenth term in this sequence A(n)= 6+(n+1)(-2) help me to find and describe the explicite formula
OleMash [197]
Hello,

A(n)=6+(n+1)^(-2)=6+1/(n+1)²

A_{4} =6+ \dfrac{1}{(4+1)^2} =6+ \dfrac{1}{25}= \dfrac{151}{25} \\

 A_{6} =6+ \dfrac{1}{(6+1)^2} =6+ \dfrac{1}{49}= \dfrac{295}{49} \\

 A_{13} =6+ \dfrac{1}{(13+1)^2} =6+ \dfrac{1}{196}= \dfrac{1177}{196} \\

7 0
3 years ago
What is the solution set?
Novay_Z [31]

Answer: x = 1 so 1/2 - 4/1 + 8 = 0n

                                 

Step-by-step explanation:

3 0
3 years ago
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