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3 years ago

Jane wants to go to her school's Prom Night. A ticket costs $120. Jane saved $30 months ago, however to earn

Mathematics

1 answer:

Anarel [89]3 years ago

5 0

Answer:

30 + 5d ≥ 120

Step-by-step explanation:

One ticket costs $120 and she already has $30 saved up so the money she makes by dogwalking added to the $30 has to be equal to or greater than 120

30 for the amount she saved up
5d where d stands for the number of days she walks dogs
Make this information into one part of the inequality: 30+5d
Then this has to be greater than or equal to 120 so:

30+5d≥120

Hope this helps!

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Nichior compared the slope of the function graphed to the slope of the linear function that has an x-intercept of 2/3 and a y-in

marusya05 [52]

Answer:

The slope of f(x) is 1.5

Step-by-step explanation:

step 1

Find the slope of the linear function that has an x-intercept of 2/3 and a y-intercept of -1

we have the points

(2/3,0) and (0,-1)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{-1-0}{0-2/3}$

$m=\frac{-1}{-2/3}$

$m=\frac{3}{2}=1.5$

step 2

Find the slope of the function graphed

take the points

(0,-1) and (3,6) approximately

substitute in the formula

$m=\frac{6+1}{3-0}$

$m=\frac{7}{3}=2.33$

step 3

we know that

f(x) represents the function with the smaller slope

The smaller slope is 1.5

therefore

The slope of f(x) is 1.5

4 0

3 years ago

Clara created the poster shown below:

lana66690 [7]

Answer:

$length=4\ cm\\width=6\ cm$

Step-by-step explanation:

Given the rectangular poster shown in the picture, you know that its dimensions (its width and its lenght) are:

$w_1=24\ cm\\l_1=16\ cm$

In order to calculate the dimensions of the rectangular at $\frac{1}{4}$ times its current size, you need to multiply the original lenght by $\frac{1}{4}$ and multiply the original width by $\frac{1}{4}$ .

Knowing this, you get:

$w_2=w_1\frac{1}{4}\\\\w_2=(24\ cm)(\frac{1}{4})\\\\w_2=6\ cm\\\\\\l_2=l_1\frac{1}{4}\\\\l_2=(16\ cm)(\frac{1}{4})\\\\l_2=4\ cm$

6 0

3 years ago

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

3 0

2 years ago

Lincoln memorial geometrical shape

meriva

Answer:

hot and sticky

Step-by-step explanation:

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3 0

3 years ago

4. Identify the graph of the solution set of 9 > 3 + 2x.

Ray Of Light [21]

Answer:

Step-by-step explanation:

9 > 3 + 2x

6 > 2x

3 > x

x < 3

and that means 3 is NOT included (otherwise there must be a smaller or equal sign). hence A is the right answer.

7 0

3 years ago