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katovenus [111]
3 years ago
12

Please help me solve this problem

Mathematics
1 answer:
IceJOKER [234]3 years ago
4 0

Answer:

OQ

Step-by-step explanation:

The lines would never hit each other going on to infinity making them parallel.

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Help?...<br> 1/3(-3) + 13
ra1l [238]

Answer: 12

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Multiple choice. Use the Law of Sines to find the missing angle of the triangle. Find m angle C to the nearest tenth if c = 111
nalin [4]

Answer:

Both A and B are possible.

Step-by-step explanation:

It's both!

This is a might tricky. First you have to find the altitude. You have to determine if this is a real triangle.

Sin(22) = opposite / hypotenuse. The hypotenuse = 111. The angle is 22

opposite = hypotenuse * sin(22)

opposite = 111 * sin(22)

opposite = 41.58  and this is the altitude.

What have you learned?

Since 42 is larger than 41.58 you have 2 solutions to the triangle. One of the angles is acute, and the other one is obtuse. They are supplementary angles.

Sin(C) / c = Sin(A) / a

Sin(C) = c * Sin(22) / 42

Sin(C) = 111*sin(22)/ 42

Sin(C) = .99003

Sin(C) = 81.9

So that's your first answer. The second answer comes from Finding the supplement to this angle

supplement + 81.9 = 180

supplement = 180 - 81.9

supplement = 98.1

7 0
3 years ago
PLEASE HELP!
Aleks04 [339]

Answer:

Option c:

0.25 \pm 1.645\sqrt{\frac{0.25*(1-0.25)}{90}}

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

For this problem, we have that:

You have access to first year enrolment records and you decide to randomly sample 119 of those records. You find that 89 of those sampled went on to complete their degree. This means that n = 119, \pi = \frac{89}{119} = 0.7478.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

Sample of 90 people with a sample proportion of 0.25

This means that n = 90, p = 0.25.

Confidence interval:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

0.25 \pm 1.645\sqrt{\frac{0.25*(1-0.25)}{90}}

Which is option c.

6 0
3 years ago
A particle moves along the plane curve C described by r(t)=ti+t2j. Find the curvature of the plane curve at t=2. Round your answ
Airida [17]

Answer:

The curvature of the plan curve at t=2 is 0.

Step-by-step explanation:

First, we find take a derivative of r(t) = ti + t^2j

r'(t) = i + 2tj

we can also write it like r'(t) = < 1, 2t>

Now, we take a magnitude of it

|r'(t)| = √(1)^2 + (2t)^2

|r'(t)| = √17

Now, we assume a variable T(t)

T(t) = r'(t)/|r'(t)|

T(t) = (i + 2tj) / √17

T(t) = 1/√17 (< 1, 2t>)

Take derivative of T(t)

T'(t) = 1/√17 (< 0, 2>)

|T'(t)| = √(1/√17)^2 + (0)^2 + (2)^2

|T'(t)| = √69/17

Therefore,

Curvature = |T'(t)| / |r'(t)|

Curvature = (√69/17) /  √17

Curvature = √69 .

5 0
3 years ago
Could someone please help me solve this problem?
Oksana_A [137]

Answer:

-9

Step-by-step explanation:

7+2n=-11

subtract 7 from 7 and -11

2n=-18

then divide 2 to both sides

and you get -9


4 0
3 years ago
Read 2 more answers
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