output of the following code fragment that invokes Twist is:
1 14 3
Explanation:
In the function Twist(),two parameters are passed. First is passed by value and second is passed by reference. If a variable is passed by value then any change made by the function will not affect the original value of that variable but when a variable is passed by reference then any change made by the function will change the original value of that variable. When Twist() function invokes with a=3 and b=2 then value of c=3+2 i.e c=5, a=3*3 i.e. a=9 (value of "a" was 3 earlier) and and b=c+a i.e b=5+9. Here only "b"is passed by reference for variable "s" then any change in it's value will be reflected in the "s". That will update the value of "s" to 14.
Answer:
The post condition is simply a statement expressing what work has been accomplished by the function. This work might involve reading or writing data, changing the values of variable parameters, or other actions.
<u>Explanation:</u>
An operating system support communication between applications through regions of memory shared between the applications. For example, a computer's RAM (random access memory) allows each running application to use a portion of the computer's memory.
I would say it is <span> B. the history of modern interior design
Because this subject stretches pretty far into history</span>
The correct answer is: Scanner
The scanner is a piece of technology which unlike the printer is an input device which basically scans the top-view of any flat surface (usually paper but is definitely not limited to it) introduced in its effective range using light. The data scanned is then transfered to the Central Processing Unit for futher processing. The processed image can then be outputted and seen on the monitor's display. Once available for printing, the Central Processing Unit will just send the processed image into the printer ad voila, your scanned image is now printed in a piece of paper!
Today, scanners come with printers as a bundle. It is a perfect combination since the printer will just print the image anyway.
