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lorasvet [3.4K]
3 years ago
7

6. the measure of angle A' Please answer

Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

Any choices or pictures??

Step-by-step explanation:

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Find the remainder in the following division problem:<br> x^5-4x^4+x^3-7x+1/x+2
icang [17]

P(x)=x^5-4x^4+x^3-7x+1,\ Q(x)=x+2\\\\P(x)=H(x)\cdot Q(x)+R

Since the polynomial degree Q(x) is 1, the remainder of the division must be a number. Therefore we only need to calculate the value of polynomial for x = -2:

P(-2)=(-2)^5-4(-2)^4+(-2)^3-7(-2)+1\\\\=-32-4(16)+(-8)+14+1\\\\=-32-64-8+15\\\\=-89

Answer: The ramainder is equal -89.

x^5-4x^4+x^3-7x+1=H(x)(x+2)-89

Calculated in the program:

x^5-4x^4+x^3-7x+1=(x^4-6x^3+13x^2-26x+45)(x+2)-89\\\Downarrow\\\dfrac{x^5-4x^4+x^3-7x+1}{x+2}=x^4-6x^3+13x^2-26x+45\ \ \ r(-89)

4 0
3 years ago
Find the measure of angle x here:
stepan [7]
The answer is A.
You subtract 90 from 75 which is 15 the you divide that by 3.
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O-4 and 2

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