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Lubov Fominskaja [6]
3 years ago
13

-3(x + 3) = -6 (x - 3) x= ?

Mathematics
1 answer:
goblinko [34]3 years ago
4 0

Answer: x= x=-\frac{-7+\sqrt{73}}{4},\:x=\frac{7+\sqrt{73}}{4}

Steps:

-3\left(x+3\right)=-6\left(x-3\right)x

− 3(x + 3 ): − 3x − 9

− 6(x − 3 )x: − 6x + 18x

-3x-9=-6x^2+18x

Switch\:sides

-6x^2+18x=-3x-9

\mathrm{Add\:}9\mathrm{\:to\:both\:sides}

-6x^2+18x+9=-3x-9+9

\mathrm{Simplify}

-6x^2+18x+9=-3x

\mathrm{Add\:}3x\mathrm{\:to\:both\:sides}

-6x^2+18x+9+3x=-3x+3x

\mathrm{Simplify}

-6x^2+21x+9=0

Solve with the quadratic formula

x_{1,\:2}=\frac{-21\pm \sqrt{21^2-4\left(-6\right)\cdot \:9}}{2\left(-6\right)}

-3(x+3) =-6 (x-3)x -

x_{1,\:2}=\frac{-21\pm \:3\sqrt{73}}{2\left(-6\right)}

\mathrm{Separate\:the\:solutions}

x_1=\frac{-21+3\sqrt{73}}{2\left(-6\right)},\:x_2=\frac{-21-3\sqrt{73}}{2\left(-6\right)}

-\frac{\sqrt{73}-7}{4}

x =2 −6−21 − 3 73:4√ 7 + 73

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=-\frac{-7+\sqrt{73}}{4},\:x=\frac{7+\sqrt{73}}{4}

Hope This Helps!

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