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Rina8888 [55]
3 years ago
8

The radius of the aluminum (Al) atom is 143 pm. The radius of the aluminum ion (Al3+) is 54 pm. By what percentage did the radiu

s change as the ion formed?

Mathematics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

There was 62.23% change in radius as the ion formed.

Step-by-step explanation:

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Find the distance between A(–3, 5) and B(4, 2), to the nearest hundredth.
sergij07 [2.7K]

Answer:

d=7.62

Step-by-step explanation:

Start with the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Identify your values.

x_1=-3\\x_2=4\\y_1=5\\y_2=2

Substitute.

d=\sqrt{(4-(-3)^2+(2-5)^2}

The -3 becomes positive as it's being multiplied by a negative.

d=\sqrt{(4+3)^2+(2-5)^2}

Solve what is in parentheses.

d=\sqrt{(7)^2+(-3)^2}

Square what is in parentheses.

d=\sqrt{49+9}

Add.

d=\sqrt{58}

Find the square root (I usually do four digits after the decimal).

d=7.6157

Round to the nearest hundredth.

d=7.62

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3 years ago
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the correct awnser is 3

Step-by-step explanation:

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Mashcka [7]
Y = –3x + 2 
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</span>
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