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patriot [66]
2 years ago
14

Lorne subtracted 6x3 – 2x + 3 from –3x3 + 5x2 + 4x – 7. Use the drop-down menus to identify the steps Lorne used to find the dif

ference.
1. (–3x3 + 5x2 + 4x – 7) + (–6x3 + 2x – 3)
2. (–3x3) + 5x2 + 4x + (–7) + (–6x3) + 2x + (–3)
3. [(–3x3) + (–6x3)] + [4x + 2x] + [(–7) + (–3)] + [5x2]
4. –9x3 + 6x + (–10) + 5x2
5. –9x3 + 5x2 + 6x – 10 ​
Mathematics
2 answers:
garri49 [273]2 years ago
8 0

Answer:

1. (–3x3 + 5x2 + 4x – 7) + (–6x3 + 2x – 3)

✔ wrote as addition of the additive inverse

2. (–3x3) + 5x2 + 4x + (–7) + (–6x3) + 2x + (–3)

✔ wrote terms as addition of opposite

3. [(–3x3) + (–6x3)] + [4x + 2x] + [(–7) + (–3)] + [5x2]

✔ grouped like terms

4. –9x3 + 6x + (–10) + 5x2

✔ combined like terms

5. –9x3 + 5x2 + 6x – 10

Step-by-step explanation:

Edge

laiz [17]2 years ago
7 0
Option 3

Rewrite the second equation and subtract the first. This is like changing the sign on every term of the first equation
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Ber [7]

Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N      Mass of the man,(m)= \frac{W}{g} = \frac{748}{9.8} = 76.32 kg

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Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is V_m .

Now using law of conservation of momentum we can find the V_m value.

m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)

Considering V_m_(_f_)=V_m

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⇒ Plugging the values.

⇒ V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}

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Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, V_m = 0.062

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know velocity(v)\times time(t) = distance(d)

Let the time taken be t and v\times t = d and d=r then, V_m\times t=r

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⇒ Plugging the values.

⇒ t=\frac{4}{0.062}

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Answer:

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Step-by-step explanation:

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