Lorne subtracted 6x3 – 2x + 3 from –3x3 + 5x2 + 4x – 7. Use the drop-down menus to identify the steps Lorne used to find the dif
ference.
1. (–3x3 + 5x2 + 4x – 7) + (–6x3 + 2x – 3)
2. (–3x3) + 5x2 + 4x + (–7) + (–6x3) + 2x + (–3)
3. [(–3x3) + (–6x3)] + [4x + 2x] + [(–7) + (–3)] + [5x2]
4. –9x3 + 6x + (–10) + 5x2
5. –9x3 + 5x2 + 6x – 10
2 answers:
Answer:
1. (–3x3 + 5x2 + 4x – 7) + (–6x3 + 2x – 3)
✔ wrote as addition of the additive inverse
2. (–3x3) + 5x2 + 4x + (–7) + (–6x3) + 2x + (–3)
✔ wrote terms as addition of opposite
3. [(–3x3) + (–6x3)] + [4x + 2x] + [(–7) + (–3)] + [5x2]
✔ grouped like terms
4. –9x3 + 6x + (–10) + 5x2
✔ combined like terms
5. –9x3 + 5x2 + 6x – 10
Step-by-step explanation:
Edge
Option 3
Rewrite the second equation and subtract the first. This is like changing the sign on every term of the first equation
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Step-by-step explanation:
∵∛x = (x)^1/3
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So you can replace the radicals by fractional exponents