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3 years ago

9

Find the energy turned into heat.

1 answer:

SOVA2 [1]3 years ago

3 0

To calculate the amount of heat released in a chemical reaction, use the equation Q = mc ΔT, where Q is the heat energy transferred (in joules), m is the mass of the liquid being heated (in kilograms), c is the specific heat capacity of the liquid (joule per kilogram degrees Celsius), and ΔT is the change in ...

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Potential energy is

azamat

Answer:

stored in a state of readiness.

Explanation:

Potential energy is stored in a state of readiness.

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

$P.E = mgh$

Where, P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

6 0

3 years ago

How much force is exerted if a 250 kg object has an acceleration of 750 m/s2 ?

Andrew [12]

Use Newton’s second law: F=ma
m= 250kg. a= 750ms-2
F= 250 x 750 = 187 500N

6 0

4 years ago

Read 2 more answers

Number of waves that pass a given point in one second

Studentka2010 [4]

<em>number of waves that pass a given point in one second is called <u>frequency..</u></em>

5 0

4 years ago

A 100-turn, 2.0-cm-diameter coil is at rest in a horizontal plane. A uniform magnetic field 60∘ away from vertical increases fro

bixtya [17]

Answer:

The induced emf is $|\epsilon|=0.0261 V$

Explanation:

From the question we are told that

The number of turn is $N = 100$

The diameter of the coil is $d = 2.0 cm = 2.0 *10^{-2} m$

The uniform magnetic at initial is $B_i = 0.50 T$

The uniform magnetic at initial is $B_f = 1.50 T$

The time taken is $t = 0.60s$

The angle the magnetic field makes with vertical is $\theta = 60^o$

Generally induced emf is mathematically represented as

$\epsilon = -N \frac{d \o}{dt}$

where $d \o$ is the change magnetic flux

Magnetic flux is mathematically represented as

$\O = \= B \cdot \= A$

$= BA cos \theta$

Substituting this above

$\epsilon = -N \frac{d (BA cos \theta)}{dt}$

$\epsilon = -N A \frac{d (B cos \theta)}{dt}$

Where B is the magnetic field and A is the area which is mathematically evaluated as

$A = \frac{\pi d^2}{4}$

Substituting values

$A = \frac{\pi (2.0 *10^{-2})^2}{4}$

$A= 3.142*10^{-4}m^2$

From the equation of emf

$\epsilon = -N A \frac{d (B cos \theta)}{dt}$

dB = $B_2 -B_1$

So

$|\epsilon| = N A \frac{ (B_2 -B_1 cos \theta)}{dt}$

substituting values

$|\epsilon| = 100(3.142*10^{-4}) \frac{ (1.50 -0.50 cos(60))}{0.60}$

$|\epsilon|=0.0261 V$

6 0

3 years ago

In a ruby laser, an electron jumps from a higher energy level to a lower one. if the energy difference between the two levels is

Vaselesa [24]

The wavelength of the emitted photon is( $\lambda$ )= 690nm

<h3>How can we calculate the wavelength of the emitted photon?</h3>

To calculate the wavelength of the photon we are using the formula,

$\triangle E= \frac{h\times c}{\lambda}$

Or, $\lambda= \frac{h\times c}{\triangle E}$

We are given here,

$\triangle E$ = The energy difference between the two levels = 1. 8 ev= $1.8\times 1.6 \times 10^{-19}$ C.

h= Planck constant = $6.626\times 10^{-34}$ Js.

c= speed of light = $3\times10^8$ m/s.

We have to find the wavelength of the emitted photon = $\lambda$ m.

Therefore, we substitute the known parameters in the above equation, we can find that,

$\lambda= \frac{h\times c}{\triangle E}$

Or, $\lambda= \frac{6.626\times 10^{-34}\times 3\times 10^8}{1.8\times 1.6 \times 10^{-19}}$

Or, $\lambda= 690\times 10^{-9}$ m

Or, $\lambda$ =690 nm.

From the above calculation we can conclude that the wavelength of the emitted photon is 690nm.

Learn more about ruby laser:

brainly.com/question/17245697

#SPJ4

8 0

2 years ago