Pleasseeeee help I’m bad
2 answers:
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Answer:
The equations in the slope-intercept form
y = - 2 x + 5
y = - 2 x + 3
Step-by-step explanation:
The slope-intercept form of the linear equation is y = m x + b, where
- m is the slope of the line.
- b is the y-intercept.
To put any equation in the slope-intercept form state y on the left side, x and the numerical term on the right side, the coefficient of y must be 1.
Let us do that with the given equations
∵ 2x + y = 5
→ Subtract 2x from both sides to move x to the right sides
∴ 2x - 2x + y = 5 - 2x
∴ y = 5 - 2x
→ Switch 5 and - 2x
∴ y = - 2x + 5
∵ 3y = 9 - 6x
→ Divide each term by 3 to make the coefficient of y = 1
∴
∴ y = 3 - 2x
→ Switch 3 and - 2x
∴ y = - 2x + 3
The equations in the slope-intercept form
y = - 2x + 5
y = - 2x + 3
Answer:
a = -1
Step-by-step explanation:
The line of symmetry for the parabola given by ...
y = ax² +bx +c
is
x = -b/(2a)
Using the given values, we have ...
-2 = -(-4)/(2a)
Multiplying by -a/2, we get ...
a = (4/2)(-1/2) = -1
The value of "a" is -1.
