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3 years ago

7

What is the probability of flipping a coin 12 times and getting heads 5 times?

1 answer:

Reptile [31]3 years ago

8 0

I don’t know if I’m right but I think the answer is B: 12.1%

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PLEASE HELP, AND SHOW WORK PLEASE!!!

Law Incorporation [45]

For number one you have to do 45.6 Divided by 2.54 to get your answer and your answer is going to be 17.95 but The answer actually continues but but sometimes there’s going to be a lot of numbers and people don’t wanna write it down so they’re just gonna cut it short I hope that kind of helped

4 0

3 years ago

How much is 79tens plus 10 tens in standard form

IrinaVladis [17]

Is it 79 sets of ten or 79 tenths

6 0

3 years ago

Read 2 more answers

Annalise earns $4 an hour walking pets in her neighborhood. She evaluates the expression 4h, where h represents the number of ho

goldfiish [28.3K]

Answer:

Yes any number can be substituted for h

Step-by-step explanation:

The term 'h' is an independent variable any number can be substituted for h, so long as the number represents the hours worked

So if she walks pets for 8 hours

Her pay is 4*8= $32

5 0

3 years ago

What is the slope<br> A. Undefined <br> B. 0

Burka [1]

B. is the correct answer love

6 0

3 years ago

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago