Answer:
Step-by-step explanation:
![As\ range=51,\\x-4=51\\x=51+4\ [Adding\ 4\ on\ both\ the\ sides]\\x=55 \\2. x\ is\ the\ lowest\ observation\ or\ x](https://tex.z-dn.net/?f=As%5C%20range%3D51%2C%5C%5Cx-4%3D51%5C%5Cx%3D51%2B4%5C%20%5BAdding%5C%204%5C%20on%5C%20both%5C%20the%5C%20sides%5D%5C%5Cx%3D55%20%5C%5C2.%20x%5C%20is%5C%20the%5C%20lowest%5C%20observation%5C%20or%5C%20x%3C4.%5C%5CHence%2C%5C%5CHighest%5C%20observation%3D48%5C%5CLowest%5C%20observation%3Dx%5C%5CHence%2C%5C%5CAs%5C%20the%5C%20range%5C%20is%5C%2051%2C%5C%5C48-x%3D51%5C%5C-x%3D51-48%20%5BSubtracting%5C%2048%5C%20from%5C%20both%5C%20the%5C%20sides%5D%5C%5C-x%3D3%5C%5Cx%3D-3)
I believe the answer is a.
Answer:
incorrect question
Step-by-step explanation:
that is what you have posted
This ends up being:
-10m = -26
M= 2.6
Basically you’re doing basic algebra. You take the “11m” and subtract it to the positive (1) m. And you basically should see 1m-11m EQUALING -10m. Don’t let the negatives confuse you.
Then you take the 20 and subtract it to -6. It should look like: -6-20 = -26.
Then divide-10 to -26, then you should get 2.6. And yes positive!!
Hope this helped!
