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3 years ago

Which set contains values of x that make the statement below TRUE?

Mathematics

1 answer:

goldenfox [79]3 years ago

3 0

Answer: the answer would be B

Step-by-step explanation:

I just had this question on my test and got it right :)

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Sam and hector are gaining weight for football season. Sam weighs 205 lbs and is gaining 2 per week. Hector weighs 195 and is ga

Sauron [17]

It takes 10 weeks for them to be the same weight

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3 years ago

Each floor in a hotel has the same number of rooms. A member of the housekeeping staff cleaning every room on 5 floors cleaned 5

ch4aika [34]

There are 10 rooms per floor if there are 30 floors then there are 300 rooms

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3 years ago

Mark ran 2 1/3 km and Shaun ran 3 1/5 km. Find the difference in the distance that they ran.

soldier1979 [14.2K]

Answer:

7/15 km

Step-by-step explanation:

Find the least common denominator between the two fractions. The least common denominator in this case would be 15, so you have to multiply 1/3 by 5 to have a denominator of 15. Then you multiply 1/5 by 3 to have a denominator of 15. You will find that Mark ran a distance of 2 5/15 km and Shaun ran 3 3/15 km. To make it even easier, you can add the whole number back into the fraction so Mark will have ran 35/15 km and Shaun will have ran 48/15 km meaning that Shaun will have ran more. Then you set you fractions up and subtract them.

6 0

3 years ago

the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region

m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

$\frac{x}{360} \pi {r}^{2}$

where x is the degrees of rotation between the two radii.

We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

$16 = \sqrt{10 {}^{2} + 10 {}^{2} - 2(100) \times \cos(o) }$

This isn't the standard formula, it's for this problem

$16 = \sqrt{200 - 200 \times \cos(o) }$

$16 = \sqrt{200 - 200 \cos(o) }$

$256 = 200 - 200 \cos(o)$

$56 = - 200 \cos(o)$

$- \frac{7}{25} = \cos(o)$

$\cos {}^{ - 1} ( - \frac{7}{25} ) = \cos {}^{ - 1} ( \cos(o) )$

$106.26 = o$

So we found our angle of rotation, which is 106.26

Now, we do the sector formula.

$\frac{106.26}{360} (100)\pi$

$\frac{10626}{360} \pi$

is the area of sector.

Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

$\sqrt{s(s - a)(s - b)(s - c)}$

where s is the semi-perimeter.

To find s, add all the side lengths up, 10,10,16 and divide it by 2.

Which is

$\frac{36}{2} = 18$

$\sqrt{18(18 - 10)(18 - 10)(18 - 16)}$

$\sqrt{18(8)(8)(2)}$

$\sqrt{(36)(64)}$

$6 \times 8 = 48$

So our area of the triangle is 48. Now, to find the shaded area subtract the main area,( the sector of the circle) by the area of the triangle so we get

$\frac{10626}{360} - 48$