Mean- 2
median- 2
mode- 1&2
range- 3
Answer:
qn 10. 15mn² - 23m²n +4m³
Step-by-step explanation:
1. distribute 4m through the parenthesis
8mn² - 12m²n + 4m³ - 2n(5m² - 3nm) + nm(n-m)
2. use the commutative property to reorder the terms
8mn² - 12m²n + 4m³ - 2n(5m² - 3mn) + mn(n - m)
3. distribute -2n through the remaining parenthesis
8mn² - 12m²n + 4m³ -10m²n + 6mn² + mn² - m²n
4. collect like terms
8mn² + 6mn² + mn² - 12m²n - 10m²n - m²n + 4m³
5. complete bodmas
15mn² - 23m²n +4m³
that's is how you do it so the answer is
15mn² -23m²n + 4m³
The inequality would be
0.75q ≥ 0.70(q+1)
q is defined as the number of questions he answers after the first one. We are told he gets 75% of those correct; 75%=75/100=0.75. This gives us 0.75q.
Since he gains proficiency on the exercises, the total number he gets correct has to be at least 70%. This means the inequality would have the symbol greater than or equal to, as it cannot be less and have him gain proficiency.
He has already answered 1 question and answers q more; this gives us a total of q+1. Since he gains proficiency, the cutoff was 70%; 70%=70/100=0.70. This gives us the expression 0.70(q+1).
Our total inequality would then be 0.75q ≥ 0.70(q+1)
Answer:
Step-by-step explanation:
Let the equal number of hours be represented by variable H;
The two equations will be as follows;
Jack; 40 +30H
Mark; 50 +25H
Next, equate them;
40 + 30H = 50 + 25H
30H - 25H = 50 - 40
5H = 10
H =10/5
H = 2hrs
Therefore, they charge the same amount at 2 hrs.
B.) The amount charged;
Replace the variable H in any of the two equations above with 2 to solve for the amount.
Equation 40+30H = 40 + (30*2)
=40 + 60
= $100
Answer:
20 seconds
Step-by-step explanation:
A is moving at the speed of 6t and B is moving at the speed of 5t. 6t +5t = 11t, and 220 divided by 11 = 20.
