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netineya [11]
3 years ago
13

1248 buttons 8 contains how many buttons will go into each contain

20" id="TexFormula1" title="1248 \div 8 = " alt="1248 \div 8 = " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Maksim231197 [3]3 years ago
7 0
Answer: 156

Explanation: it’s a simple equation really. Just divide 1248 by 8. Calculators work wonders, just telling you in advance.
Oksanka [162]3 years ago
4 0

Answer:

156 buttons in each container

Step-by-step explanation:

\frac{1248}{8}  = 156

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Find the solution of the differential equation that satisfies the given initial condition. (du)/(dt) = (2t + sec^2 t)/(2u), u(0)
Delicious77 [7]
Ah okay so in differential equations you usually want the top variable isolated. To do this, multiply by dt and 2u and you get
2udu = 2t + { \sec(t) }^{2} dt
Now just integrate both sides. The integral of 2u with respect to u is u². The integral of (2t + sec²(t) with respect to t is t² + ∫sec²(t)dt. The last part is just tan(x) because d/dt(tan(t)) is sec²(t) so just integrating gets us back. Now we have
{u}^{2}   + c =  {t}^{2}  +  \tan(t)  + k
Where c and k are arbitrary constants. Subtracting c from k and you get
{u}^{2}  =  {t}^{2}  +  \tan(t)  + b
Where b is another constant. To find b, just plug in u(0) = -1 where u is -1 and t is 0. This becomes
1 =  \tan(0)  + b
tan(0) is 0 so b = 1. Take the plus or minus square root on both sides and you finally get
u =  \: { {t}^{2} }  +  \tan(t)  + 1
But Brainly didn't let me do but juat remember there is a plus or minus square root on the left.
3 0
3 years ago
Find the exact value without a calculator. Tan 7pi/12=sin7pi/6/2 /cos7pi/6/2
lara31 [8.8K]

Answer:

458

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A square and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of
krek1111 [17]

Answer:

Step-by-step explanation:

it is given that Square contains a chord of of the circle equal to the radius thus from diagram

QR=chord =radius =R

If Chord is equal to radius then triangle PQR is an equilateral Triangle

Thus QO=\frac{R}{2}=RO

In triangle PQO applying Pythagoras theorem

(PQ)^2=(PO)^2+(QO)^2

PO=\sqrt{(PQ)^2-(QO)^2}

PO=\sqrt{R^2-\frac{R^2}{4}}

PO=\frac{\sqrt{3}}{2}R

Thus length of Side of square =2PO=\sqrt{3}R

Area of square=(\sqrt{3}R)^2=3R^2

Area of Circle=\pi R^2

Ratio of square to the circle=\frac{3R^2}{\pi R^2}=\frac{3}{\pi }

5 0
3 years ago
Don't go by my answers pls
Illusion [34]

Answer:

19)  ( \frac{-2}{5})^2 = \frac{4}{25}

20) -9^{2} = -81

21)  2^{4} = 16

Step-by-step explanation:

The only wrong ones are

19)  ( \frac{-2}{5})^2 = \frac{4}{25}

20) -9^{2} = -81 ... negative is not inside a parenthesis that's why it is still negative

21) you can add another way is 2^{4} = 16

Everything else looks good.  Great job!

4 0
2 years ago
Is this correct?? if not pls tell me the correct answer
slamgirl [31]

Answer:

no, but it is A.

8 0
2 years ago
Read 2 more answers
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