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3 years ago

6

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1 answer:

katrin [286]3 years ago

7 0

Answer:

Step-by-step explanation:

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How do I solve (4x+1)(x-5)=-43x-41

AfilCa [17]

Remember you can do anything to an equation as long as you do it to both sides
expand by foiling or distributing

4x²-19x-5=-43x-41
add 43x to both sides and add 41 to both sides

4x²+24x+36=0
factor
facotr out of 4
4(x²+6x+9)=0
factor inside
what 2 numbers multiply to get 9 and add to get 6?
3 and 3
4(x+3)(x+3)=0
set to 0

x+3=0
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x=-3 is answer

8 0

3 years ago

Aaa help pls with this question

amm1812

It wont open it up, so no one can really help

7 0

3 years ago

A triangle has two 12‑centimeter sides. Which of the following CANNOT be the length of the third side? A. 12 cm B. 6 cm C. 24 cm

Juliette [100K]

Answer:

C.

Step-by-step explanation:

The sum of two sides have to be greater than than the third (Triangle Inequality Theorem). 24 is equal to 24, not greater.

5 0

4 years ago

Read 2 more answers

Solve each equation for y. 3x + 2 =6y

Strike441 [17]

Answer:

1/2x + 1/3 = y

Step-by-step explanation:

3x + 2 =6y

Divide each side by 6

3x/6 + 2/6 = 6y/6

Simplify

1/2x + 1/3 = y

6 0

4 years ago

The output of a chemical process is continually monitored to ensure that the concentration remains within acceptable limits. Whe

marissa [1.9K]

Answer:

a) 0.31 = 31%

b) 0.03 = 3%

c) 0.36 = 36%

d) 2 times

Step-by-step explanation:

If $F_X(x)$ is the cumulative distribution function of the random variable X, then by definition the probability P of the random variable is given by

$P(X \leq x) = F_X(x)$

If additionally the random variable is discrete (only has non-negative integers as outcomes as is the case in this problem) then

$P(X=a)=F_X(a)-\lim_{x \to a^-}F_X(x)$

a)

We are looking for P(X<2)

$P(X < 2) = P(X\leq 2)-P(X=2)=F_X(2)-\lim_{x \to 2^-}F_X(x)=0.84-0.53=0.31$

b)

In this case we want P(X>3)

$P(X >3) = 1-P(X\leq 3)=1-F_X(3)=1-0.97=0.03$

c)

Now, we are interested in P(X=1)

$P(X =1) =F_X(1)-\lim_{x \to 1^-}F_X(x)=0.53-0.17=0.36$

d)

The expected number of times that the process is recalibrated during the week is the expected value of the probability distribution:

P(X=1)+2P(X=2)+...+nP(X=n)+...

But it is easy to see that P(X=n) = 0 if n is an integer >4

So, the expected value is

P(X=1)+2P(X=2)+3P(X=3)+4P(X=4)

We already have P(X=1) and P(X=2). Let's compute the rest

$P(X =3) =F_X(3)-\lim_{x \to 3^-}F_X(x)=0.97-0.84=0.13$

$P(X =4) =F_X(4)-\lim_{x \to 4^-}F_X(x)=1-0.97=0.03$

and the expected value is

0.36 + 2*0.53+3*0.13+4*0.03= 1.93 = 2 times rounding to the nearest integer.

8 0

4 years ago