Question

How do I solve (4x+1)(x-5)=-43x-41

Answer 1

Remember you can do anything to an equation as long as you do it to both sides
expand by foiling or distributing


4x²-19x-5=-43x-41
add 43x to both sides and add 41 to both sides

4x²+24x+36=0
factor
facotr out of 4
4(x²+6x+9)=0
factor inside
what 2 numbers multiply to get 9 and add to get 6?
3 and 3
4(x+3)(x+3)=0
set to 0

x+3=0
x=-3

x=-3 is answer