How do I solve (4x+1)(x-5)=-43x-41
1 answer:
Remember you can do anything to an equation as long as you do it to both sides
expand by foiling or distributing
4x²-19x-5=-43x-41
add 43x to both sides and add 41 to both sides
4x²+24x+36=0
factor
facotr out of 4
4(x²+6x+9)=0
factor inside
what 2 numbers multiply to get 9 and add to get 6?
3 and 3
4(x+3)(x+3)=0
set to 0
x+3=0
x=-3
x=-3 is answer
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