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andriy [413]
3 years ago
15

.Write the equation of the line that passes through (5,0) and is perpendicular to the line y = 5x + 55.​

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0

Answer:

y=-1/5 x+c

0=-1/5(5)+c

0=-1+c

1=c

y=-1/5x+1

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
What is the first step when rewriting y = 3x2 9x – 18 in the form y = a(x – h)2 k?
stiks02 [169]
A quadratic equation has the general form of: <span>

y=ax² + bx + c

It can be converted to the vertex form in order to determine the vertex of the parabola. It has the standard form of:

y = a(x+h)² - k

This can be done by completing a square. The steps are as follows:

</span><span>y = 3x2 + 9x – 18
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</span>
Therefore, the first step is to group terms with the variable x and factoring out the coefficient of x^2.
3 0
3 years ago
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SVETLANKA909090 [29]

Answer:

p=36^{\circ}

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We can prove that a tangent will always be perpendicular to the radius touching it. So, the other angle in the diagram is 90^{\circ}.

Because all the angles of a triangle sum to 180^{\circ}, we have that p+54+90=180.

We combine like terms on the left side to get p+144=180.

We subtract 144 on both sides to get p=36.

So, \boxed{p=36^{\circ}} and we're done!

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2 years ago
If 2*3=10, 3*5=13, what is 4*7?
Mrac [35]
It should be 16, but because there is only 2 examples, I'm not totally sure. But, I hope this helps you! :)
3 0
3 years ago
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